我目前正在重构我的方法。 我已经淘汰了很长的foreach,如果状态,但现在我在最后一次完成时有点挣扎,有一个很好的地图功能。
我的方法看起来像。
/**
* @param \Illuminate\Support\Collection
* @return array
*/
public static function convertTimesToChartData($times) {
$clientTotal = '0';
$arrayIndex = 0;
$chartData = collect($times)->filter(function($item) {
return !is_null($item->end_time);
})->map(function($item) use(&$clientTotal, &$arrayIndex){
$clients[$arrayIndex]['id'] = $item->client_id;
$clients[$arrayIndex]['project_id'] = $item->project_id;
$clients[$arrayIndex]['label'] = $item->company;
$clients[$arrayIndex]['sec'] = $item->end_time->timestamp - $item->start_time->timestamp;
$clientTotal += $item->end_time->timestamp - $item->start_time->timestamp;
$arrayIndex++;
return $clients;
})->flatMap(function($item) { return $item; });
return $chartData;
}
在这里,我有两个问题:
有没有更好的方法来分配数组?当我试图直接在回报中分配
时 return [
[$arrayIndex]['id'] => $item->client_id,
[$arrayIndex]['project_id'] => $item->project_id,
[$arrayIndex]['label'] => $item->company,
[$arrayIndex]['sec'] => $item->end_time->timestamp - $item->start_time->timestamp,
];
但后来我得到一个未定义的索引错误。
以下是原始资料来源:
$projects = array();
$projectTotal = '0';
foreach($taskTimes as $time){
if(!is_null($time->end_time))
{
if (isset($projects[$time->project_id]))
{
$projects[$time->project_id]['sec'] += $time->end_time->timestamp - $time->start_time->timestamp;
} else
{
$projects[$time->project_id]['id'] = $time->client_id;
$projects[$time->project_id]['label'] = $time->company;
$projects[$time->project_id]['sec'] = $time->end_time->timestamp - $time->start_time->timestamp;
}
$projectTotal += $time->end_time->timestamp - $time->start_time->timestamp;
}
}
感谢您的任何建议和帮助!
答案 0 :(得分:1)
为了获得与原始foreach循环相同的结果,您可以这样:
$projects = collect($taskTimes)
->filter(function ($time) {
return !is_null($time->end_time);
})
->groupBy('project_id')
->map(function ($group) {
$group = collect($group);
return [
'id' => $group->first()->client_id,
'project_id' => $group->first()->project_id,
'label' => $group->first()->company,
'sec' => $group->sum(function ($item) {
return $item->end_time->timestamp - $item->start_time->timestamp;
}),
];
});
$projectsTotal = $projects->sum('sec');
我已将project_id
添加到生成的数组中,因为它包含在convertTimesToChartData()
方法示例中
希望这有帮助!