SELECT tbl_music.id,
tbl_music.name,
tbl_music.img,
tbl_music.date,
tbl_music.post,
COUNT(*) AS comms,
COUNT(*) AS liky
FROM tbl_music
LEFT JOIN tbl_mlikes
ON tbl_music.id = tbl_mlikes.mid
LEFT JOIN tbl_mus_coms
ON tbl_music.id = tbl_mus_coms.mid
WHERE tbl_music.status = 'Publish'
GROUP BY tbl_music.id
ORDER BY tbl_music.id
DESC
我注意到的是它将评论数量与喜欢的数量相乘并提供答案作为喜欢的数量即(如果帖子有4个评论和1个喜欢,我的查询将显示4个评论和4个喜欢)这真是令人沮丧
答案 0 :(得分:1)
问题是你有两个不同的维度,因此查询会为每个音乐ID生成一个笛卡尔积。
最佳解决方案是在加入之前聚合:
SELECT m.*, l.likes, c.comments
FROM tbl_music m LEFT JOIN
(SELECT mid, COUNT(*) as likes
FROM tbl_mlikes
GROUP BY mid
) l
ON m.id = l.mid LEFT JOIN
(SELECT mc.mid, COUNT(*) as comments
FROM tbl_mus_coms mc
GROUP BY mc.mid
) c
ON m.id = c.mid
WHERE m.status = 'Publish'
ORDER BY m.id DESC ;