Question

我是PowerShell的新手，无法理解为什么会出现以下错误

Invoke-Command：找不到接受参数的位置参数＆＃39; d：\部署\ file.zip＆＃39 ;. 在D：\ source \ Scripts \ Build-Deploy \ Build-Deploy \ ServersDeploy.ps1：105 char：5

Invoke-Command -ComputerName $ servers -ScriptBlock {
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~
- CategoryInfo：InvalidArgument：（:) [Invoke-Command]，ParameterBindingException
- FullyQualifiedErrorId：PositionalParameterNotFound，Microsoft.PowerShell.Commands.InvokeCommandCommand

这是正在运行的脚本

params([string[[]]$servers, [string]$dest_package_path, [string]$src_package_path,[string]$deploy_script)

Invoke-Command -ComputerName $servers -ScriptBlock {
    param($dest_package_path,$src_package_path,$deploy_script) 
    Write-Output "Destination path = $dest_package_path"
    Write-Output "Copying zip $src_package_path to the destination host"
    New-Item -ItemType Directory -Force -Path $dest_package_path
    Write-Output "Directory Created"
    Copy-Item -Path $src_package_path -Destination $dest_package_path -Force        

    Write-Host "Copying remote deploy scripts to the destination host"
    Copy-Item -Path $deploy_script -Destination $dest_package_path -Force
} -ArgumentList $dest_package_path $src_package_path $deploy_script

Answer 1

因为您使用空格而不是逗号分隔参数。这使他们成为a := (a dependsOn b).value的新论据。

Invoke-Command一个带数组的参数：

-ArgumentList

使用带有ScriptBlock和-ArgumentList的Invoke-Command时出现问题

1 个答案: