Question

我有一个方法：

public JsonResult Layar(string countryCode, string timestamp, string userId, 
                        string developerId, string layarName, double radius, 
                        double lat, double lon, double accuracy)
{
    LayarModel model = new LayarModel(lat, lon, radius);

    return Json(model, JsonRequestBehavior.AllowGet);
}

它返回此对象：

public class LayarModel
{        
    private List<HotSpot> _hotSpots = new List<HotSpot>();
    public List<HotSpot> HotSpots { get { return _hotSpots; } set { _hotSpots = value; } }    
    public string Name { get; set; }    
    public int ErrorCode { get; set; }
    public string ErrorString { get; set; }
}

我想让JSON成为

{"hotspots": [{
    "distance": 100, 
    "attribution": "The Location of the Layar Office", 
    "title": "The Layar Office",  
    "lon": 4884339, 
    "imageURL": http:\/\/custom.layar.nl\/layarimage.jpeg,
    "line4": "1019DW Amsterdam",
    "line3": "distance:%distance%",
    "line2": "Rietlandpark 301",
    "actions": [],
    "lat": 52374544,
    "type": 0,
    "id": "test_1"}], 
 "layer": "snowy4",
 "errorString": "ok", 
 "morePages": false,
 "errorCode": 0,
 "nextPageKey": null
}

所有内容都在返回的类中大写（HotSpots而不是hotspots）。

我尝试过DataContract和DataMembers（Name =“Test”），但这不起作用。有什么建议吗？

Answer 1

JsonResult（）在内部使用JavaScriptSerializer进行序列化，似乎它不支持使用属性定义序列化属性名称。

DataContractJsonSerializer支持这一点，因此这可能是一种方法。

一些可能有用的链接：

JavaScriptSerializer.Deserialize - 如何更改字段名称：JavaScriptSerializer.Deserialize - how to change field names
DataContractJsonSerializer与JavaScriptSerializer：更改字段名称：http://publicityson.blogspot.com/2010/06/datacontractjsonserializer-versus.html

Answer 2

我还建议安装json.NET，但其余的更容易。下面是我在当前应用程序中使用的扩展方法，以提供更好的重用，随意使其适应您的需求，但它应该开箱即用。

public class JsonNetResult : ActionResult
{
    public Encoding ContentEncoding { get; set; }
    public string ContentType { get; set; }
    public object Data { get; set; }

    public JsonSerializerSettings SerializerSettings { get; set; }
    public Formatting Formatting { get; set; }

    public JsonNetResult()
    {
        SerializerSettings = new JsonSerializerSettings
            {
                //http://odetocode.com/blogs/scott/archive/2013/03/25/asp-net-webapi-tip-3-camelcasing-json.aspx
                #if DEBUG
                Formatting = Formatting.Indented, //Makes the outputted Json easier reading by a human, only needed in debug
                #endif
                ContractResolver = new CamelCasePropertyNamesContractResolver() //Makes the default for properties outputted by Json to use camelCaps
            };
    }

    public override void ExecuteResult(ControllerContext context)
    {
        if (context == null)
            throw new ArgumentNullException("context");

        HttpResponseBase response = context.HttpContext.Response;

        response.ContentType = !string.IsNullOrEmpty(ContentType)
                                    ? ContentType
                                    : "application/json";

        if (ContentEncoding != null)
            response.ContentEncoding = ContentEncoding;

        if (Data != null)
        {
            JsonTextWriter writer = new JsonTextWriter(response.Output) {Formatting = Formatting};

            JsonSerializer serializer = JsonSerializer.Create(SerializerSettings);
            serializer.Serialize(writer, Data);

            writer.Flush();
        }
    }
}

public static class JsonNetExtenionMethods
{
    public static ActionResult JsonNet(this Controller controller, object data)
    {
        return new JsonNetResult() {Data = data};
    }

    public static ActionResult JsonNet(this Controller controller, object data, string contentType)
    {
        return new JsonNetResult() { Data = data, ContentType = contentType };
    }

    public static ActionResult JsonNet(this Controller controller, object data, Formatting formatting)
    {
        return new JsonNetResult() {Data = data, Formatting = formatting};
    }
}

以下是使用它的一个例子。

public JsonNetResult Layar(string countryCode, string timestamp, string userId, 
                        string developerId, string layarName, double radius, 
                        double lat, double lon, double accuracy)
{
    LayarModel model = new LayarModel(lat, lon, radius);

    return this.JsonNet(model);
}

需要注意的部分是，ContractResolver上的JsonSerializerSettings设置为使用new CamelCasePropertyNamesContractResolver()

时，具体解决您的问题

这样您就不必再次设置自定义命名。

JsonResult相当于[DataMember（Name =“Test”）]

2 个答案: