以下是我们的设备传输定制服务的自定义特性的定期更新。此设备中的服务和特性是通过XML文件定义的。当然,这是指蓝牙BLE协议。
我要做的是创建一个简单的Qt Android应用程序,它连接到设备并监控更新。我已经发现了服务并将信号连接到它。我已经使用此代码完成了这项工作:
void BLETest::on_stateChanged(QLowEnergyService::ServiceState state){
Q_UNUSED(state);
// Only printing data if all services are in correct state.
for (qint32 i = 0; i < monitoredServices.size(); i++){
if (monitoredServices.at(i)->state() != QLowEnergyService::ServiceDiscovered){
logger->out("There are still services that have not been discoverd",Logger::LC_ORANGE);
return;
}
}
QString msg = "PRINTING SERVICE DATA<br>";
for (qint32 i = 0; i < monitoredServices.size(); i++){
QLowEnergyService *monitoredService = monitoredServices.at(i);
QList<QLowEnergyCharacteristic> clist = monitoredService->characteristics();
msg = msg + "SERVICE: " + monitoredService->serviceName() + ". UUID: " + monitoredService->serviceUuid().toString() + "<br>";
// Checking if this is the service that need connection.
if (monitoredService->serviceUuid() == QBluetoothUuid(QString("0a464eef-af72-43fd-8a8b-1f26f6319dab"))){
QString res;
if (connect(monitoredService,SIGNAL(characteristicChanged(QLowEnergyCharacteristic,QByteArray)),this,SLOT(on_charastericChanged(QLowEnergyCharacteristic,QByteArray)))) res = "true";
else res = "false";
logger->out("CONNECTED TO TARGET SERVICE: " + res,Logger::LC_ORANGE);
}
for (int i = 0; i < clist.size(); i++){
QString name = clist.at(i).name();
if (name.isEmpty()) name = "UNDEFINED NAME";
QByteArray buffer = clist.at(i).value();
//QString value = QString(clist.at(i).value());
QString value = QByteArray(buffer.toHex()) + " (BS = " + QString::number(buffer.size()) + ")";
QString properties = QString::number(clist.at(i).properties());
msg = msg + "CHARACTERISTIC: " + clist.at(i).uuid().toString() + " - " + name + ": " + value + ". PROPERTIES: " + properties + "<br>";
}
if (clist.isEmpty()){
msg = msg + "No characteristics found<br>";
}
}
logger->out(msg);
}
上述函数等待发现所有服务,然后为所有服务的所有特征打印UUID,名称和值。当处理我想要监视的服务时,将对changedCharacteristic信号进行连接。
当我这样做时,我要监视的服务特征的打印值是该特征的原始值。但是,当该值更新时,我没有得到通知(信号永远不会触发),因此我的应用中的值永远不会改变。
我是否需要编写一些代码来实际触发信号?
PD:使用Blue Gecko Demo App我可以看到值的变化。
编辑:我决定使用计时器来轮询特征的值,它永远不会改变。这可能表明为什么信号永远不会产生。
答案 0 :(得分:0)
您应该将一个特性改变的处理程序连接到服务:
import UIKit
import Material
@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate {
var window: UIWindow?
func applicationDidFinishLaunching(_ application: UIApplication) {
let pageTabBarController = AppPageTabBarController(viewControllers: [RedViewController(), GreenViewController(), BlueViewController()], selectedIndex: 0)
window = UIWindow(frame: Screen.bounds)
window!.rootViewController = AppNavigationController(rootViewController: pageTabBarController)
window!.makeKeyAndVisible()
}
}
在插槽中,您可以浏览数据数组。
但是,如果启用了此特征通知,则信号(characteristicChanged())将仅由服务发出。这仅适用于characteritic具有notify属性的情况,即应用程序中的情况。