悲观情节和箱线异常值

Question

我试图摆脱我的图中包含箱线图和贝叶的异常值。

我用以下行创建了boxplot：

boxplot(Lead_s ~ Group, data = g, outline = FALSE, 
    main = 'Gaze shift duration with co-occuring movement units',
    horizontal=TRUE,xlab = "Gaze lead (sec)")

随着outline=FALSE我的异常值消失。

然后，我运行此代码以蜜蜂群的形式获取我的数据点。

beeswarm(Lead_s ~ Group, data = g, col = 4, pch = 16, 
    add = TRUE,horizontal=TRUE,pwcol = 1 + as.numeric(Lead_s))

蜜蜂群的箱线图：

如果outliers被绘制在图表之外，会发生什么。无论我是否添加outline=FALSE，异常值仍然存在。

这是我绘制的数据样本：

Group           Lead_s
Non-Performers  1
Non-Performers  3
Expert  18
Non-Performers  0.1
Non-Performers  0.1
Non-Performers  0.1
Non-Performers  0.2
Non-Performers  0.2
Non-Performers  0.3
Expert  0.4
Non-Performers  0.4
Non-Performers  0.4
Expert  0.5
Non-Performers  0.5
Non-Performers  0.6
Non-Performers  0.6
Non-Performers  0.7
Expert  0.8
Non-Performers  0.8
Expert  1.1
Expert  1.1
Non-Performers  1.1
Expert  1.3
Non-Performers  1.3
Non-Performers  1.4
Non-Performers  1.4
Non-Performers  1.4
Non-Performers  1.5
Expert  1.7
Expert  1.9
Non-Performers  1.9
Expert  2.1
Non-Performers  2.1
Non-Performers  2.1
Non-Performers  2.1
Non-Performers  2.3
Expert  2.5
Expert  2.7
Expert  2.7
Non-Performers  3.1
Expert  4.1
Expert  4.5
Non-Performers  5.6
Non-Performers  6.7

任何想法我该如何解决？

Answer 1

您似乎有非默认＆＃39; xpd＆＃39; （剪辑）设置。 （见export interface CommonInputProp{ id:Number; value?:String; displayName?:String; order?:Number; viewVal:String=this.value|this.displayName; // This is not supported now } ）

要获得默认行为（不显示绘图区域之外的任何点），您可以在绘图命令之前设置xpd：

?par