问题
如上所述。我有一个代码示例如下所示。
$mapItems = array(
array("id" => 1, "title" => "map pin 1", "xcoord" => "420", "ycoord" => "120"),
array("id" => 2, "title" => "map pin 2", "xcoord" => "429", "ycoord" => "129"),
array("id" => 3, "title" => "map pin 3", "xcoord" => "329", "ycoord" => "329")
);
问题是,我想从数据库中获取数据并放入如上所示的数组中。我尝试过,但我不知道它是如何运作的。以下是我的一些代码:
$mapItems = array();
$qry='SELECT l.loc_x, l.loc_y, m.member_name '.
'FROM location l '.
'JOIN member m ON m.member_id = l.member_id '.
"WHERE l.map_id = '$id'";
$result=mysqli_query($con, $qry);
$tempNo=1;
while($rows=mysqli_fetch_array($result)){
$mapItems["id"] = $tempNo;
$mapItems["title"] = $rows['member_name'];
$mapItems["xcoord"] = $rows['loc_x'];
$mapItems["ycoord"] = $rows['loc_y'];
$tempNo++;
}
我想制作底部代码,看起来与顶级代码完全相同,但是通过从数据库中读取数据。提前谢谢。
解
最后,我设法为我的问题找到解决方案。
$qry='SELECT l.loc_x, l.loc_y, m.member_name '.
'FROM location l '.
'JOIN member m ON m.member_id = l.member_id '.
"WHERE l.map_id = '$id'";
$result=mysqli_query($con, $qry);
$i=1;
$mapItems = array();
while($rows=mysqli_fetch_array($result)){
$loc = array("id" => $i,
"title" => $rows['member_name'],
"xcoord" => $rows['loc_x'],
"ycoord" => $rows['loc_y']);
$mapItems[] = $loc;
$i++;
}
参考:dropPin
答案 0 :(得分:0)
试试这个
$i = 0; //array index
while($rows=mysqli_fetch_array($result)){
$mapItems[$i]["id"] = $tempNo;
$mapItems[$i]["title"] = $rows['member_name'];
$mapItems[$i]["xcoord"] = $rows['loc_x'];
$mapItems[$i]["ycoord"] = $rows['loc_y'];
$tempNo++;
$i++;
}
答案 1 :(得分:0)
我希望这会对你有所帮助
$qry="SELECT l.loc_x, l.loc_y, m.member_name FROM location l JOIN member m ON m.member_id = l.member_id WHERE l.map_id = '$id'";
$result=mysqli_query($con, $qry);
$mapItems = array();
$tempNo=1;
while($rows=mysqli_fetch_array($result)) {
$mapItems[] = $row;
}
print_r($mapItems);