Question

我有一个清单

x=[1,2,0,0,0,3,0,0,0,0,0,4]

我想减去列表

y=[0,0,0]

来自清单x

所以结果应该是

z=[1,2,3,0,0,4]

我如何在python中实现这一目标？编辑 - 请注意我不是要替换我试图删除

Answer 1

在我看来，你需要寻找匹配的索引，然后使用切片赋值替换它们：

x=[1,2,0,0,0,3,0,0,0,0,0,4]
y=[0,0,0]

# Search for all non-overlapping occurences of `y`
ix = 0
matches = []
while ix < len(x):
    if x[ix:ix + len(y)] == y:
        matches.append(ix)
        ix += len(y)
    else:
        ix += 1

# Replace them with slice assignment.
for ix in reversed(matches):
    x[ix:ix + len(y)] = []

print(x)

Answer 2

这是我的方法，找到x[0]的索引列表，然后删除子列表。

x=[1,2,0,0,0,3,0,0,0,0,0,4]
y=[0,0,0]


def sub(x, y):
    for i in [index for index, value in enumerate(x) if value == y[0]]:
        if x[i:i + len(y)] == y:
            x[i:i + len(y)] = [None] * len(y)

    return filter(lambda k: k != None, x)


print sub(x,y)

感谢@ mgilson，我修复了一个错误。

Answer 3

x=[1,2,0,0,0,3,0,0,0,0,0,4]
y=[0,0,0]
z = []

foundForThisPass = False
indexsSame = []

for a in range (0, len(y)):
  for b in range(0, len(x)):
    if (y[a] == x[b] and foundForThisPass == False):
      indexsSame.append(b)
      foundForThisPass = True

  foundForThisPass = False


i = 0
for a in range (0, len(x)):
  if (a == indexsSame[i]):
    i += 1
  else:
    z.append(x[a])

print(z)

Answer 4

这是一种愚蠢的方式：

import json

xs = repr(x)[1:-1]
ys = repr(y)[1:-1]

new_x = json.loads((''.join(xs.split(ys))).replace(',,',','))

从python中的另一个列表中删除一个完整的列表

4 个答案: