Question

要求用户输入2到10之间的整数，将整数分配给变量x。
当x小于500时，在循环内执行以下操作：

2.1。打印x的当前值

2.2。更新x，使其比以前的值加倍
退出循环后，打印x的最终值和循环输入的次数。

这就是我所做的我只是不明白如何让python计算循环次数。

x = int(input("Enter an integer between 2 and 10: "))

while x < 500:

    print (x)

    x = x+x

print('The final value of x is', x)

print("The loop was entered, )

示例输出：

Enter an integer between 2 and 10: 10
10
20
40
80
160
320
The final value of x is 640
The loop was entered 6 times.

Enter an integer between 2 and 10: 3
3
6
12
24
48
96
192
384
The final value of x is 768
The loop was entered 8 times.

如果有人可以解释最后一串代码，我将不胜感激！

Answer 1

解决方案可以是这样的：

cnt = 0
x = int(input("Enter an integer between 2 and 10: "))
while x < 500:
    print (x)
    x = x+x
    cnt = cnt+1

print('The final value of x is', x)

print('The loop was entered', cnt)

如何显示循环输入的次数？

1 个答案: