我已经更改了我的启动器活动,而不是.MainActivity
。当我的应用程序在后台时,Firebase推送通知服务不起作用,但当应用程序位于前台时,它可以正常工作。
我在我的应用中添加了WelcomeSlider
,这就是为什么我必须将欢迎滑块保持为启动器活动的原因。我检查过,如果我将启动器活动更改为NotifyActivity
,那么它再次正常工作。
这是我的AndroidManifest.xml
<application
android:allowBackup="true"
android:icon="@drawable/logo"
android:label="@string/app_name"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity
android:name=".WelcomeActivity"
android:label="@string/app_name"
android:theme="@style/AppTheme.NoActionBar"
>
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity
android:name=".MainActivity"
android:configChanges="orientation|screenSize"
android:label="@string/app_name"
android:theme="@style/AppTheme.NoActionBar" />
<activity
android:name=".Vlog"
android:parentActivityName=".MainActivity" />
<activity android:name=".NotifyActivity"></activity>
<service android:name=".MyFirebaseMessagingService">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
<service android:name=".MyFirebaseInstanceIdService">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
</application>
这是myFirebaseInstanceIdService:
public class MyFirebaseInstanceIdService extends FirebaseInstanceIdService {
@Override
public void onTokenRefresh(){
String token = FirebaseInstanceId.getInstance().getToken();
Log.d("TOKEN",token);
}
}
这是myFirebaseMessagingService:
public class MyFirebaseMessagingService extends FirebaseMessagingService {
private static final String TAG = "MyFirebaseMsgService";
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
Intent intent = new Intent(this,NotifyActivity.class);
if(remoteMessage.getData().size()>0){
String url = remoteMessage.getData().get("url");
Bundle bundle = new Bundle();
bundle.putString("url",url);
intent.putExtras(bundle);
}
intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
PendingIntent pendingIntent = PendingIntent.getActivity(this,0,intent,PendingIntent.FLAG_ONE_SHOT);
NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this);
notificationBuilder.setContentTitle(remoteMessage.getNotification().getTitle());
notificationBuilder.setContentText(remoteMessage.getNotification().getBody());
notificationBuilder.setAutoCancel(true);
notificationBuilder.setSmallIcon(R.mipmap.notifyicon);
Uri sound= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
notificationBuilder.setSound(sound);
notificationBuilder.setContentIntent(pendingIntent);
NotificationManager notificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
notificationManager.notify(0,notificationBuilder.build());
notificationBuilder.setVibrate(new long[] { 1000, 1000, 1000, 1000, 1000 });
}
}
答案 0 :(得分:2)
我已经自己解决了这个问题。我只是将MainActivity
作为Android Manifest
的启动器活动保持
<activity
android:name=".MainActivity"
android:label="@string/app_name"
android:theme="@style/AppTheme.NoActionBar"
>
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
并在MainActivity
onCreate
内张贴下方的代码,以检查它是否第一次启动!
//Check if it first time launching..
Boolean isFirstRun = getSharedPreferences("PREFERENCE", MODE_PRIVATE)
.getBoolean("isFirstRun", true);
if (isFirstRun) {
//show start activity
startActivity(new Intent(MainActivity.this, WelcomeActivity.class));
Toast.makeText(MainActivity.this, "First Run", Toast.LENGTH_LONG)
.show();
}
它对我有用! :) :)