我有一个Printf格式问题。我要打印10个数字,然后再转到下一行并再打印10个数字,依此类推。最终目标就像一张桌子,所有列都排成一行并与右边对齐。我也在使用while语句。我尝试过在研究中发现的一些不同的东西,但没有成功。除Printf之外,我会使用不同的print语句吗?如Print或PrintLn?还考虑过使用If语句。任何帮助将不胜感激!谢谢。
System.out.printf("Please enter a maximun integer value: ");
Scanner scan = new Scanner(System.in);
double n = scan.nextDouble();
System.out.printf("The number you entered was: %.0f \n", n); // Just to check if user input is correct
double startNum = 0;
double sqrt = startNum;
System.out.printf("Squares less than %.0f are: ", n);
while ( sqrt < n) {
sqrt = Math.pow(startNum, 2);
System.out.printf("%6.0f", sqrt);
startNum ++;
}
答案 0 :(得分:1)
使用MOD条件,您可以确保每行10个输出。
import java.util.Scanner;
class Test {
public static void main(String[] args) {
System.out.printf("Please enter a maximun integer value: ");
Scanner scan = new Scanner(System.in);
double n = scan.nextDouble();
System.out.printf("The number you entered was: %.0f \n", n); // Just to check if user input is correct
double startNum = 0;
double sqrt = startNum;
System.out.printf("Squares less than %.0f are: ", n);
while (sqrt < n) {
sqrt = Math.pow(startNum, 2);
if(startNum != 0 && startNum % 10 == 0) {
System.out.println();
}
System.out.printf("%6.0f", sqrt);
startNum++;
}
}
}
输出 -
请输入最大整数值:150
您输入的数字是:150
小于150的正方形是:0 1 4 9 16 25 36 49 64 81
121 144 169
答案 1 :(得分:0)
if(deviceIsMobile) {
jQuery('#PickupTime').attr('type','date');
} else {
jQuery('#PickupTime').datetimepicker(dateTimeOptions);
}