Question

我写了一个函数，在单击箭头时左右移动滑块。滑块的工作原理是更改网址中的哈希值。

功能：

var navigateGalleryForward = function() {
   var pathName = window.location.href;
   if (pathName.indexOf("item-1") != -1) {
     window.location.hash = "item-2";
   } else if (pathName.indexOf("item-2") != -1) {
     window.location.hash = "item-3";
   } else if (pathName.indexOf("item-3") != -1) {
     window.location.hash = "item-1";
   } else {
     console.log("Something went wrong navigating the gallary..")
   }
 };
 var navigateGalleryBackward = function() {
    var pathName = window.location.href;
    if (pathName.indexOf("item-1") != -1) {
      window.location.hash = "item-3";
    } else if (pathName.indexOf("item-2") != -1) {
      window.location.hash = "item-1";
    } else if (pathName.indexOf("item-3") != -1) {
      window.location.hash = "item-2";
    } else {
      console.log("Something went wrong navigating the gallary..")
    }
  };

$(document).ready(function() {
 $("#left-arrow").on('click', function () {
   console.log("I work");
   navigateGalleryBackward();
 });
 $("#right-arrow").on('click', function () {
   console.log('work');
   navigateGalleryForward();
 });
});

箭头示例：

<figure class="item one">
      <img onClick="navigateGalleryBackward" id="left-arrow" src="{{ 'arrow-left.png' | asset_url }}" alt="left">
      <img onclick="navigateGalleryForward" id="right-arrow"src="{{ 'arrow-right.png' | asset_url }}" alt="right">
      <h1 style="color: white; font-weight:bold; font-size: 2rem; margin-top:2em; ">5 New Sensors for Control4</h1>
      <p style="color: white; font-size:1.2rem;">Learn more about Dome's new line of cross-compatible sensors.</p>
      <img style="height: 150px; margin-top: 3em; margin-right: 3em;"class="figure_h" src="{{ 'slide_show_1.jpg' | asset_url }}" />
      <button style="margin-top: 3em; display:block; margin: auto;" class="btn_k">BUY NOW</button>
  </figure>

所以在图一，它的确有效。但在第二和第三位上它并没有。它被解雇后，它不会再次开火。

图二和三：

<figure class="item two">
    <img onClick="navigateGalleryBackward" id="left-arrow" src="{{ 'arrow-left.png' | asset_url}}" alt="left">
    <img onclick="navigateGalleryForward" id="right-arrow" src="{{ 'arrow-right.png' | asset_url }}" alt="right">
    <h1 class="figure_h">2</h1>
  </figure>



    <figure class="item three">
        <img onClick="navigateGalleryBackward" id="left-arrow" src="{{ 'arrow-left.png' | asset_url }}" alt="left">
        <img onclick="navigateGalleryForward" id="right-arrow" src="{{ 'arrow-right.png' | asset_url }}" alt="right">
        <h1 class="figure_h">3</h1>
      </figure>

我怎样才能使这个工作？

谢谢！

Answer 1

你的箭头都有相同的ID，试着给它们一个类，然后在你的脚本中使用它。

Answer 2

HTML元素id对于两个或更多元素不能相同。

单击jQuery只触发一次

2 个答案: