Question

我正在尝试根据类属性动态地向我的pandas.DataFrame添加一行，但由于某种原因它不起作用。希望一个例子更有意义：

import numpy as np
import pandas as pd

class match:
def __init__(self):
    self.position = np.zeros(shape = (3, 3))
    self.moves = []

def PlayMove(self, x_coordinate, y_coordinate, player_name):
    if player_name == "player1":
        self.position[x_coordinate, y_coordinate] = 1
    if player_name == "player2":
        self.position[x_coordinate, y_coordinate] = 4
    self.moves.append(pd.DataFrame(self.position.reshape(1, 9)))

match1 = match()
match1.PlayMove(1,2,"player1")
print(match1.position)
print(match1.moves)
match1.PlayMove(2,2,"player1")
print(match1.position)
print(match1.moves)

这两次输出相同的动作，而我想保存第一个动作，第二个动作保存在单独的行中。每次播放一个动作时，我想在match1.moves中保存一个新位置，在match1.position中保存最后一个位置。

Answer 1

您的实施存在一些问题。

如果您想要一个DataFrame，则self.move不应该是列表
如果您希望每行都有独特的电路板快照，则每次保存时都需要复制电路板。

<强>代码：

class match:
    def __init__(self):
        self.position = np.zeros(shape=(3, 3))
        self.moves = None

    def PlayMove(self, x_coordinate, y_coordinate, player_name):
        if player_name == "player1":
            self.position[x_coordinate, y_coordinate] = 1
        else:
            self.position[x_coordinate, y_coordinate] = 4
        move = pd.DataFrame(np.array(self.position).reshape(1, 9))
        self.moves = pd.concat([self.moves, move])

测试代码：

match1 = match()
match1.PlayMove(1, 2, "player1")
print(match1.position)
print('\n1:\n', match1.moves)
match1.PlayMove(2, 2, "player2")
print('\n', match1.position)
print('\n2:\n', match1.moves)

<强>结果：

[[ 0.  0.  0.]
 [ 0.  0.  1.]
 [ 0.  0.  0.]]

1:
     0    1    2    3    4    5    6    7    8
0  0.0  0.0  0.0  0.0  0.0  1.0  0.0  0.0  0.0

[[ 0.  0.  0.]
 [ 0.  0.  1.]
 [ 0.  0.  4.]]

2:
     0    1    2    3    4    5    6    7    8
0  0.0  0.0  0.0  0.0  0.0  1.0  0.0  0.0  0.0
0  0.0  0.0  0.0  0.0  0.0  1.0  0.0  0.0  4.0

根据class属性动态添加行到DataFrame

1 个答案: