Question

while True:
    profilePassword = input("Password: ")
    if profilePassword == "":
        print("Your password can't be blank!")
        continue
    else:
        pass
    for n in profilePassword:
        if n == " ":
            print("Your password can't contain spaces!")
            break
        elif n not in "1234567890":
            print("Your password has to contain at least one number!")
            break
        elif n not in "abcdefghijklmnopqrstuvwxyz":
            print("Your password has to contain at least one lowercase letter!")
            break
        elif n not in "ABCDEFGHIJKLMNOPQRSTUVWXYZ":
            print("Your password has to contain at least one uppercase letter!")
            break
        else:
            continue

所以我正在尝试创建一个检查密码是否正确的程序。由于某种原因＆＃34;不在＆＃34;不是表现得很好。如果我写，例如，asd123，它会说密码必须至少包含一个数字，它具有。为什么这样，我该如何解决？

Answer 1

正如评论所说，你正在检查每个char是否为数字（如果是，第二个elif失败，因为你检查它是否是一个字符）。这不是你想要做的，你只是想确保整个字符串包含一个数字。

您可以使用regex：

if re.search(regex, password):
    # regex found something
else:
    # no match

我个人认为最好告诉用户所有失败的事情（不是第一次失败）。

import re

def setPassword(profilePassword):
    msg = ""
    if re.search(r' ', profilePassword):
        msg += "* Your password can't contain spaces!\n"

    if not re.search(r'\d', profilePassword):
        msg += "* Your password has to contain at least one number!\n"

    if not re.search(r'[a-z]', profilePassword):
        msg += "* Your password has to contain at least one lowercase letter!\n"

    if not re.search(r'[A-Z]', profilePassword):
        msg += "* Your password has to contain at least one uppercase letter!\n"

    if msg == "":
        print("Setting password was successfull")
    else:
        print("Setting password was not successfull due to following reasons:")
        print(msg)



setPassword("")
setPassword(" ")
setPassword("a")
setPassword("A")
setPassword("1")

setPassword("asd123")

setPassword("aA1")

while True:
    profilePassword = input("Password: ")
    if profilePassword == "":
        print("Your password can't be blank!")
        continue
    else:
        pass
    setPassword(profilePassword)

在搜索时也发现了这一点：Checking the strength of a password (how to check conditions)

Answer 2

不要做循环。转换密码以设置和检查交叉点，顺序如下：

digits = set("0123456789")
pw = set("password")
if not digits.intersection(pw):
     # no digits in password

如何检查一封信中是否有字母？

2 个答案: