Question

var fruitsVeg = ["apple", "orange", "banana", "tomato", "onion"];

if（fruitsVeg包含＆＃34;番茄＆＃34;或＆＃34;洋葱＆＃34;或＆＃34;番茄和洋葱＆＃34;）

alert("your array has only vegetables");

if（fruitsVeg包含＆＃34; apple＆＃34;或＆＃34; orange＆＃34;或＆＃34; banana＆＃34;或＆＃34; apple和orange＆＃34;或＆＃34; apple和香蕉＆＃34;或＆＃34;橙和香蕉＆＃34;）然后

alert("your array has only fruits");

if（fruitsVeg仅包含来自水果的元素和仅来自蔬菜的元素，即var fruitsVeg = ["apple", "orange", "tomato", "onion"];）

alert("your array has both fruits and vegetables");

Answer 1

可读性优先示例：使用indexOf()创建条件，例如：

＆＃13;

var fruitsVeg = ["apple", "orange", "banana", "tomato", "onion"];
var isVege = fruitsVeg.indexOf("tomato") > - 1 || fruitsVeg.indexOf("onion") > -1
var isFruit = fruitsVeg.indexOf("orange") > - 1 || fruitsVeg.indexOf("apple") > -1 || fruitsVeg.indexOf("banana") > -1;

if(isVege && isFruit)
    console.log("your array has both fruits and vegetables");
else if (isVege)
    console.log("your array has only vegetables");
else if (isFruit)
    console.log("your array has only fruits");

＆＃13;

效果优先示例：如果bool包含两种类型的植物，则在单个循环中为所有项目分配break值，并fruitsVeg分配var fruitsVeg = ["apple", "orange", "banana", "tomato", "onion"]; var isVege = false; var isFruit = false; function fruit(item) { return item === "apple" || item === "banana" || item === "orange"; } function vege(item) { return item === "tomato" || item === "onion"; } for(var i = 0; i < fruitsVeg.length; i++) { var item = fruitsVeg[i]; if(isVege && isFruit) { console.log("Both."); break; } else if (vege(item)) { isVege = true; } else if (fruit(item)) { isFruit = true; } } if( !(isVege && isFruit) ) { if(isVege) console.log("Vege"); else if(isFruit) console.log("Fruit"); }值：LoginManager.getInstance() .logInWithReadPermissions(MainActivity.this, new ArrayList<String>(AccessToken.getCurrentAccessToken().getDeclinedPermissions()) );

＆＃13;

AddWithValue

＆＃13;

Answer 2

琐碎版

var alert = console.log.bind(console) // for demo purposes

var fruitsVeg = ["apple", "orange", "banana", "tomato", "onion"];

var hasFruits = fruitsVeg.includes("tomato") || fruitsVeg.includes("onion")
var hasVeges = fruitsVeg.includes("apple") || fruitsVeg.includes("orange") || fruitsVeg.includes("banana")

if (hasFruits && hasVeges) alert("both fruits and vegetables")
else if (hasFruits) alert("only fruits")
else alert("only vegetables")

编辑：我想我也会尝试一个更高效的例子，因为为什么不呢！

快速版

var alert = console.log.bind(console) // for demo purposes

var fruitsVeg = ["apple", "orange", "banana", "tomato", "onion"];

var hasFruits = false,
    hasVeges = false

if (fruitsVeg.some(function(e) {
    if (/^(tomato|onion)$/.test(e)) hasVeges = true
    else if (/^(apple|orange|banana)$/.test(e)) hasFruits = true
    return hasFruits && hasVeges
})) {
  alert('both fruits and vegetables')
} else {
  alert(hasFruits ? 'only fruits' : 'only vegetables')
}

如何根据数组

2 个答案:

琐碎版

快速版