从表格列中检索数字并用文字打印的查询是什么？ 例如：-data是72 它应该打印为七十二。
答案 0 :(得分：1)
我知道没有RDBMS有这样的功能，即使你可以写一个作为udf或sproc的大多数数据库都有深度字符串处理。在您的客户端应用中执行此操作。
答案 1 :(得分：1)
我们在项目中使用的完全相同。没有内置的方法，但我有一个功能，你可以试试你的结果。希望这会对你有所帮助 - 当然你可以调整你的要求 -
CREATE FUNCTION [dbo].[NumberToWords]
(
@NumberString nvarchar(max)
) RETURNS VARCHAR(8000)
AS BEGIN
DECLARE @Number Numeric (38, 0)
DECLARE @inputNumber VARCHAR(38)
DECLARE @NumbersTable TABLE (number CHAR(2), word VARCHAR(10))
DECLARE @outputString VARCHAR(8000)
DECLARE @length INT
DECLARE @counter INT
DECLARE @loops INT
DECLARE @position INT
DECLARE @chunk CHAR(3)
DECLARE @tensones CHAR(2)
DECLARE @hundreds CHAR(1)
DECLARE @tens CHAR(1)
DECLARE @ones CHAR(1)
set @Number = cast( @NumberString as Numeric (38, 0) )
IF @Number = 0 Return 'Zero'
-- initialize the variables
SELECT @inputNumber = CONVERT(varchar(38), @Number)
, @outputString = ''
, @counter = 1
SELECT @length = LEN(@inputNumber)
, @position = LEN(@inputNumber) - 2
, @loops = LEN(@inputNumber)/3
-- make sure there is an extra loop added for the remaining numbers
IF LEN(@inputNumber) % 3 <> 0 SET @loops = @loops + 1
-- insert data for the numbers and words
INSERT INTO @NumbersTable SELECT '00', ''
UNION ALL SELECT '01', 'one' UNION ALL SELECT '02', 'two'
UNION ALL SELECT '03', 'three' UNION ALL SELECT '04', 'four'
UNION ALL SELECT '05', 'five' UNION ALL SELECT '06', 'six'
UNION ALL SELECT '07', 'seven' UNION ALL SELECT '08', 'eight'
UNION ALL SELECT '09', 'nine' UNION ALL SELECT '10', 'ten'
UNION ALL SELECT '11', 'eleven' UNION ALL SELECT '12', 'twelve'
UNION ALL SELECT '13', 'thirteen' UNION ALL SELECT '14', 'fourteen'
UNION ALL SELECT '15', 'fifteen' UNION ALL SELECT '16', 'sixteen'
UNION ALL SELECT '17', 'seventeen' UNION ALL SELECT '18', 'eighteen'
UNION ALL SELECT '19', 'nineteen' UNION ALL SELECT '20', 'twenty'
UNION ALL SELECT '30', 'thirty' UNION ALL SELECT '40', 'forty'
UNION ALL SELECT '50', 'fifty' UNION ALL SELECT '60', 'sixty'
UNION ALL SELECT '70', 'seventy' UNION ALL SELECT '80', 'eighty'
UNION ALL SELECT '90', 'ninety'
WHILE @counter <= @loops BEGIN
-- get chunks of 3 numbers at a time, padded with leading zeros
SET @chunk = RIGHT('000' + SUBSTRING(@inputNumber, @position, 3), 3)
IF @chunk <> '000' BEGIN
SELECT @tensones = SUBSTRING(@chunk, 2, 2)
, @hundreds = SUBSTRING(@chunk, 1, 1)
, @tens = SUBSTRING(@chunk, 2, 1)
, @ones = SUBSTRING(@chunk, 3, 1)
-- If twenty or less, use the word directly from @NumbersTable
IF CONVERT(INT, @tensones) <= 20 OR @Ones='0'
BEGIN
SET @outputString = (SELECT word
FROM @NumbersTable
WHERE @tensones = number)
+ CASE @counter WHEN 1 THEN '' -- No name
WHEN 2 THEN ' thousand ' WHEN 3 THEN ' million '
WHEN 4 THEN ' billion ' WHEN 5 THEN ' trillion '
WHEN 6 THEN ' quadrillion ' WHEN 7 THEN ' quintillion '
WHEN 8 THEN ' sextillion ' WHEN 9 THEN ' septillion '
WHEN 10 THEN ' octillion ' WHEN 11 THEN ' nonillion '
WHEN 12 THEN ' decillion ' WHEN 13 THEN ' undecillion '
ELSE '' END
+ @outputString
END
ELSE BEGIN -- break down the ones and the tens separately
SET @outputString = ' '
+ (SELECT word
FROM @NumbersTable
WHERE @tens + '0' = number)
+ '-'
+ (SELECT word
FROM @NumbersTable
WHERE '0'+ @ones = number)
+ CASE @counter WHEN 1 THEN '' -- No name
WHEN 2 THEN ' thousand ' WHEN 3 THEN ' million '
WHEN 4 THEN ' billion ' WHEN 5 THEN ' trillion '
WHEN 6 THEN ' quadrillion ' WHEN 7 THEN ' quintillion '
WHEN 8 THEN ' sextillion ' WHEN 9 THEN ' septillion '
WHEN 10 THEN ' octillion ' WHEN 11 THEN ' nonillion '
WHEN 12 THEN ' decillion ' WHEN 13 THEN ' undecillion '
ELSE '' END
+ @outputString
END
-- now get the hundreds
IF @hundreds <> '0' BEGIN
SET @outputString = (SELECT word
FROM @NumbersTable
WHERE '0' + @hundreds = number)
+ ' hundred '
+ @outputString
END
END
SELECT @counter = @counter + 1
, @position = @position - 3
END
SET @outputString = LTRIM(RTRIM(REPLACE(@outputString, ' ', ' ')))
SET @outputstring = UPPER(LEFT(@outputstring, 1)) + SUBSTRING(@outputstring, 2, 8000)
RETURN @outputString
END
答案 2 :(得分：0)
我不相信有内置功能，但这是一个很好的起点。
http://www.novicksoftware.com/udfofweek/Vol2/T-SQL-UDF-Vol-2-Num-9-udf_Num_ToWords.htm
我们在这里谈论哪种SQL？
也就是说，由于您正在有效地转换数据，这实际上是在您的业务甚至表示层中完成的事情
修改
辉煌！只是自己测试一下：
select dbo.udf_Num_ToWords(19264235677575674234234234234223123123)
十九个十亿不朽二百 六十四十亿二百 三十五十亿六百 七十七点五十五 七十五个septillion六百 七十四个性欲二百 三十四个五十分之一 三十四万亿二百 三十四万二百 三十四亿两百 二千三百万 二万三千一百 23
： - ）
第二次编辑后的评论
修改了包含'和'的功能：
CREATE FUNCTION dbo.udf_Num_ToWords (
@Number Numeric (38, 0) -- Input number with as many as 18 digits
) RETURNS VARCHAR(8000)
/*
* Converts a integer number as large as 34 digits into the
* equivalent words. The first letter is capitalized.
*
* Attribution: Based on NumberToWords by Srinivas Sampath
* as revised by Nick Barclay
*
* Example:
select dbo.udf_Num_ToWords (1234567890) + CHAR(10)
+ dbo.udf_Num_ToWords (0) + CHAR(10)
+ dbo.udf_Num_ToWords (123) + CHAR(10)
select dbo.udf_Num_ToWords(76543210987654321098765432109876543210)
DECLARE @i numeric (38,0)
SET @i = 0
WHILE @I <= 1000 BEGIN
PRINT convert (char(5), @i)
+ convert(varchar(255), dbo.udf_Num_ToWords(@i))
SET @I = @i + 1
END
*
* Published as the T-SQL UDF of the Week Vol 2 #9 2/17/03
****************************************************************/
AS BEGIN
DECLARE @inputNumber VARCHAR(38)
DECLARE @NumbersTable TABLE (number CHAR(2), word VARCHAR(10))
DECLARE @outputString VARCHAR(8000)
DECLARE @length INT
DECLARE @counter INT
DECLARE @loops INT
DECLARE @position INT
DECLARE @chunk CHAR(3) -- for chunks of 3 numbers
DECLARE @tensones CHAR(2)
DECLARE @hundreds CHAR(1)
DECLARE @tens CHAR(1)
DECLARE @ones CHAR(1)
DECLARE @interim VARCHAR(8000)
IF @Number = 0 Return 'Zero'
-- initialize the variables
SELECT @inputNumber = CONVERT(varchar(38), @Number)
, @outputString = ''
, @counter = 1
SELECT @length = LEN(@inputNumber)
, @position = LEN(@inputNumber) - 2
, @loops = LEN(@inputNumber)/3
-- make sure there is an extra loop added for the remaining numbers
IF LEN(@inputNumber) % 3 <> 0 SET @loops = @loops + 1
-- insert data for the numbers and words
INSERT INTO @NumbersTable SELECT '00', ''
UNION ALL SELECT '01', 'one' UNION ALL SELECT '02', 'two'
UNION ALL SELECT '03', 'three' UNION ALL SELECT '04', 'four'
UNION ALL SELECT '05', 'five' UNION ALL SELECT '06', 'six'
UNION ALL SELECT '07', 'seven' UNION ALL SELECT '08', 'eight'
UNION ALL SELECT '09', 'nine' UNION ALL SELECT '10', 'ten'
UNION ALL SELECT '11', 'eleven' UNION ALL SELECT '12', 'twelve'
UNION ALL SELECT '13', 'thirteen' UNION ALL SELECT '14', 'fourteen'
UNION ALL SELECT '15', 'fifteen' UNION ALL SELECT '16', 'sixteen'
UNION ALL SELECT '17', 'seventeen' UNION ALL SELECT '18', 'eighteen'
UNION ALL SELECT '19', 'nineteen' UNION ALL SELECT '20', 'twenty'
UNION ALL SELECT '30', 'thirty' UNION ALL SELECT '40', 'forty'
UNION ALL SELECT '50', 'fifty' UNION ALL SELECT '60', 'sixty'
UNION ALL SELECT '70', 'seventy' UNION ALL SELECT '80', 'eighty'
UNION ALL SELECT '90', 'ninety'
WHILE @counter <= @loops BEGIN
-- get chunks of 3 numbers at a time, padded with leading zeros
SET @chunk = RIGHT('000' + SUBSTRING(@inputNumber, @position, 3), 3)
IF @chunk <> '000' BEGIN
SELECT @tensones = SUBSTRING(@chunk, 2, 2)
, @hundreds = SUBSTRING(@chunk, 1, 1)
, @tens = SUBSTRING(@chunk, 2, 1)
, @ones = SUBSTRING(@chunk, 3, 1)
-- If twenty or less, use the word directly from @NumbersTable
IF CONVERT(INT, @tensones) <= 20 OR @Ones='0' BEGIN
SELECT @interim = word
FROM @NumbersTable
WHERE @tensones = number
if rtrim(ltrim(isnull(@interim,''))) <> ''
begin
set @interim = 'and ' + @interim
end
SET @outputString = @interim
+ CASE @counter WHEN 1 THEN '' -- No name
WHEN 2 THEN ' thousand ' WHEN 3 THEN ' million '
WHEN 4 THEN ' billion ' WHEN 5 THEN ' trillion '
WHEN 6 THEN ' quadrillion ' WHEN 7 THEN ' quintillion '
WHEN 8 THEN ' sextillion ' WHEN 9 THEN ' septillion '
WHEN 10 THEN ' octillion ' WHEN 11 THEN ' nonillion '
WHEN 12 THEN ' decillion ' WHEN 13 THEN ' undecillion '
ELSE '' END
+ @outputString
END
ELSE BEGIN -- break down the ones and the tens separately
SET @outputString = ' '
+ (SELECT 'and ' + isnull(word,'')
FROM @NumbersTable
WHERE @tens + '0' = number)
+ '-'
+ (SELECT word
FROM @NumbersTable
WHERE '0'+ @ones = number)
+ CASE @counter WHEN 1 THEN '' -- No name
WHEN 2 THEN ' thousand ' WHEN 3 THEN ' million '
WHEN 4 THEN ' billion ' WHEN 5 THEN ' trillion '
WHEN 6 THEN ' quadrillion ' WHEN 7 THEN ' quintillion '
WHEN 8 THEN ' sextillion ' WHEN 9 THEN ' septillion '
WHEN 10 THEN ' octillion ' WHEN 11 THEN ' nonillion '
WHEN 12 THEN ' decillion ' WHEN 13 THEN ' undecillion '
ELSE '' END
+ @outputString
END
-- now get the hundreds
IF @hundreds <> '0' BEGIN
SET @outputString = (SELECT word
FROM @NumbersTable
WHERE '0' + @hundreds = number)
+ ' hundred '
+ @outputString
END
END
SELECT @counter = @counter + 1
, @position = @position - 3
END
-- Remove any double spaces
SET @outputString = LTRIM(RTRIM(REPLACE(@outputString, ' ', ' ')))
SET @outputstring = UPPER(LEFT(@outputstring, 1)) + SUBSTRING(@outputstring, 2, 8000)
RETURN @outputString -- return the result
END
答案 3 :(得分：0)
您可以为数字翻译创建一个单独的表（如果您希望以后支持更多语言，可能每个语言有一列），然后通过连接表来检索单词。类似的东西：
SELECT table_with_translations.en
FROM table_with_numbers
JOIN table_with_translations ON table_with_numbers.number = table_with_translations.en;
WHERE table_with_numbers.number = 72;
不是最复杂的方法，我不认为这会扩展得太好，但如果你需要一个快速的解决方案并且项目相当小，那么这应该可以正常工作。
答案 4 :(得分：0)
就个人而言，我会通过创建一个permananet表并用数字和单词填充它来完成此操作。我不知道你需要多大这个，但是将这些单词插入一个表（它不会像它们将要改变的那样）比使用函数来确定单词要有效得多。如果您需要使用此（或更高版本）进入数百万，您可以创建脚本以使用上述函数作为起始位置生成表的数据。
如果您打算经常进行此转换，那么您可以加入的具有良好索引的表将是性能最佳的方法。