在MYSQL中查找2个不同列中特定id的max（sum）

Question

我的表格看起来像

我需要特定team_id的目标总和 例如：
如果team_id 16分别得分6和2，则另一个新列sum_goal中的总和为8

我无法继续下去。请帮助。

我尝试的查询是：

选择（match_id，Sum（Goal）From     （     从match_result_updation中选择team1_id ID，team1_goal目标     联盟全部     从match_result_updation中选择team2_id ID，team2_goal目标     ）

as A)

这

（SELECT  c.tournament_id，g。*
来自team_trophies d 内部联接 tournament_match e 上 e.tournament_id = d.tournament_id 内部联接 tournament_scheduling c 上 c.tournament_id = e.tournament_id 内部联接 匹配f 上 f.match_id = c.id 内部联接 match_result_updation g 上 g.match_id = f.id 哪里 f.match_type ='锦标赛' 和 d.tournament_id = 1）作为p 按比例分组

从第二个选择到id = 1我得到了附件图片中的输出，但是我无法找到每个team_id的目标总和。 如果teamid 16或17，则team1或team2相应地计算目标总和。

Answer 1

我的第一个想法是将它们放入列中，然后求和。 编辑任何SQL引擎

Select ID, Sum(Goal) From
    (
    Select Team1_ID ID, Team1_Goal Goal From Table
    Union All
    Select Team2_ID ID, Team2_Goal Goal From Table
    ) A
Group By ID

ps如果表格设计规范化，则不需要这种解决方法。

Answer 2

使用此查询有助于实现目标总和

select team1_id, sum(team1_goal) as sum_goal from `table` group by `team1_id`;

Answer 3

我们也可以这样做....

select team1_id, sum(team1_goal) as sum_goal from `table` group by `team1_id`
union all
select team2_id, sum(team2_goal) as sum_goal from `table` group by `team1_id`;

如果你想再次总结，那么可以像这样使用

select t.team_id, sum(t.sum_goal) as total_goal from (
  select team1_id as team_id, sum(team1_goal) as sum_goal from `table` group by `team1_id`
  union all
  select team2_id as team_id, sum(team2_goal) as sum_goal from `table` group by `team1_id`
) as t group by t.team_id;

Answer 4

试试这个

Select ID, Sum(Goal) From
(
Select Team1_ID ID, Team1_Goal Goal From Table
Union All
Select Team2_ID ID, Team2_Goal Goal From Table
)l,
table_name Group By ID

Answer 5

另一个版本：

SELECT SUM(nr) 
FROM (
    (SELECT sum(team1_goal) as nr FROM goals WHERE team1_id = 16)
    UNION ALL
    (SELECT sum(team2_goal) as nr FROM goals WHERE team2_id = 16)
)
sum

Answer 6

SELECT team1_id AS Team_ID , sum(team1_goal) as Team_Goal       
FROM 
teams GROUP BY team1_id
UNION
SELECT team2_id AS Team_ID  , sum(team2_goal) as Team_Goal
FROM teams GROUP BY team2_id

这将创建一个表，其中包含每个团队的ID以及每个团队ID的目标总数