在C中我们如何读取和生成具有低字和高字以及低字节和高字节的DWORD
变量?
答案 0 :(得分:6)
WinAPI为这些类型的操作提供了宏,例如:
答案 1 :(得分:2)
在Win32中,DWORD是32位无符号整数。在其他情况下,它可能意味着别的东西。
说明Win32定义(以及其他Win32 typedef):
BYTE lsb = 0x11 :
BYTE next_lsb = 0x22 :
BYTE next_msb = 0x33 :
BYTE msb = 0x44 :
DWORD dword_from_bytes = (msb << 24) | (next_msb << 16) | (next_lsb << 8) | lsb ;
dword_from_bytes
的值为0x44332211
。
类似地:
WORD lsw = 0x1111 :
WORD msw = 0x2222 :
DWORD dword_from_words = (msw << 16) | lsw ;
dword_from_words
的值为0x22221111
。
例如从<{1}}中提取第三个字节:
dword_from_bytes
虽然next_msb = (dword_from_bytes >> 16) & 0xff ;
在这种情况下并不是绝对必要的,但是如果接收器的类型大于8位,它将掩盖msb位。
答案 2 :(得分:0)
#include <stdint.h>
#include <stdio.h>
typedef union _little_endian{
struct _word{
union _msw{
struct _msw_byte{
uint8_t MSB;
uint8_t LSB;
} __attribute__((__packed__)) MSW_BYTE;
uint16_t WORD;
} MSW;
union _lsw{
struct _lsw_byte{
uint8_t MSB;
uint8_t LSB;
} __attribute__((__packed__)) LSW_BYTE;
uint16_t WORD;
} LSW;
} __attribute__((__packed__)) WORD;
uint32_t DWORD;
} DWORD;
int main(int argc, char *argv[]){
DWORD test1;
test1.WORD.MSW.MSW_BYTE.MSB = 1;
test1.WORD.MSW.MSW_BYTE.LSB = 2;
test1.WORD.LSW.LSW_BYTE.MSB = 3;
test1.WORD.LSW.LSW_BYTE.LSB = 4;
printf("test1: hex=%x uint=%u\n", test1.DWORD, test1.DWORD);
DWORD test2;
test2.DWORD = 0x08080404;
printf("test2: hex=%x uint=%u\n", test2.DWORD, test2.DWORD);
printf("test2.WORD.MSW.MSW_BYTE.MSB: uint=%u\n", test2.WORD.MSW.MSW_BYTE.MSB);
printf("test2.WORD.MSW.MSW_BYTE.LSB: uint=%u\n", test2.WORD.MSW.MSW_BYTE.LSB);
printf("test2.WORD.LSW.LSW_BYTE.MSB: uint=%u\n", test2.WORD.LSW.LSW_BYTE.MSB);
printf("test2.WORD.LSW.LSW_BYTE.LSB: uint=%u\n", test2.WORD.LSW.LSW_BYTE.LSB);
return 0;
}
我更喜欢结合使用结构和联合。
输出:
test1: hex=4030201 uint=67305985
test2: hex=8080404 uint=134743044
test2.WORD.MSW.MSW_BYTE.MSB: uint=4
test2.WORD.MSW.MSW_BYTE.LSB: uint=4
test2.WORD.LSW.LSW_BYTE.MSB: uint=8
test2.WORD.LSW.LSW_BYTE.LSB: uint=8