我最近将iText7项目从7.0.1升级到7.0.2。之后,我尝试重建我的项目并进行单元测试。单元测试给了我一个错误,然后我尝试调试单元测试。结果是我之前从未发现过一个奇怪的异常......代码是相同的,但它在v7.0.1上运行顺利,但是在v7.0.2上遇到了异常:
异常消息:
“Nullable对象必须有值。”
异常StackTrace:
在System.ThrowHelper.ThrowInvalidOperationException(ExceptionResource 资源)在iText.Layout.Renderer.TableRenderer.Layout(LayoutContext) layoutContext)at iText.Layout.Renderer.RootRenderer.AddChild(IRenderer渲染器)at iText.Layout.RootElement`1.Add(IBlockElement元素)at iText.Layout.Document.Add(IBlockElement元素)at C:\ Users \ Jeffry中的KMK_Core.Core._Core_PrintKMK() Angtoni \ Source \ Repos \ kmk-core-ng \ KMK NG \ KMK Core \ Core.cs:第332行
下面是我的表生成器代码:
Table tblStudentIdentity = new Table(new float[] { 3.5f, .2f, 5f });
tblStudentIdentity.SetWidthPercent(80f);
_Core_SetIdentityTableValue(ref tblStudentIdentity, "NAMA", "Name", "LEONARDO DICAPRIO");
_Core_SetIdentityTableValue(ref tblStudentIdentity, "NIM", "Student Number", "1301566255");
_Core_SetIdentityTableValue(ref tblStudentIdentity, "FAKULTAS / SEKOLAH", "Faculty/School", "", "School of Computer Science");
tblStudentIdentity.SetRelativePosition(115f, 20f, 0f, 0f);
_doc.Add(tblStudentIdentity);
下面是我的_Core_SetIdentityTableValue函数:
private int _Core_SetIdentityTableValue(ref Table tableObject, string LeftLabelID = "", string LeftLabelEN = "", string RightValueID = "", string RightValueEN = "")
{
int Result = 0;
Text txtOpenInfo = new Text("(").AddStyle(StyleHelper.lblIDStyle);
Text txtCloseInfo = new Text(")").AddStyle(StyleHelper.lblIDStyle);
Text txtColonInfo = new Text(":").AddStyle(StyleHelper.lblIDStyle);
Paragraph lblLeftPrgrh = new Paragraph();
if (LeftLabelEN != "" && LeftLabelID != "")
{
Text lblID = new Text(LeftLabelID + " ").AddStyle(StyleHelper.lblIDStyle);
Text lblEN = new Text(LeftLabelEN).AddStyle(StyleHelper.lblENStyle);
lblLeftPrgrh.Add(lblID).Add(txtOpenInfo).Add(lblEN).Add(txtCloseInfo);
}else if (LeftLabelEN == "" && LeftLabelID != "")
{
Text lblID = new Text(LeftLabelID).AddStyle(StyleHelper.lblIDStyle);
lblLeftPrgrh.Add(lblID);
}else if (LeftLabelEN != "" && LeftLabelID == "")
{
Text lblEN = new Text(LeftLabelEN).AddStyle(StyleHelper.lblENStyle);
lblLeftPrgrh.Add(lblEN);
}else
{
Text lblErrorLeft = new Text("Error-NoValue");
lblLeftPrgrh.Add(lblErrorLeft);
Result = 1;
}
Paragraph lblRightPrgrh = new Paragraph();
if (RightValueEN != "" && RightValueID != "")
{
Text lblValID = new Text(RightValueID + " ").AddStyle(StyleHelper.lblIDStyle);
Text lblValEN = new Text(RightValueEN).AddStyle(StyleHelper.lblENStyle);
lblRightPrgrh.Add(lblValID).Add(txtOpenInfo).Add(lblValEN).Add(txtCloseInfo);
}else if (RightValueEN == "" && RightValueID != "")
{
Text lblValID = new Text(RightValueID).AddStyle(StyleHelper.lblIDStyle);
lblRightPrgrh.Add(lblValID);
}else if (RightValueEN != "" && RightValueID == "")
{
Text lblValEN = new Text(RightValueEN).AddStyle(StyleHelper.lblENStyle);
lblRightPrgrh.Add(lblValEN);
}else
{
Text lblValError = new Text("Error-NoValue");
lblRightPrgrh.Add(lblValError);
Result = 1;
}
Paragraph lblCenterPrgrh = new Paragraph(txtColonInfo);
Cell cellLeft = new Cell();
cellLeft.Add(lblLeftPrgrh)
.SetBorder(Border.NO_BORDER)
.SetVerticalAlignment(VerticalAlignment.TOP);
Cell cellMiddle = new Cell();
cellMiddle.Add(lblCenterPrgrh)
.SetBorder(Border.NO_BORDER)
.SetVerticalAlignment(VerticalAlignment.TOP);
Cell cellRight = new Cell();
cellRight.Add(lblRightPrgrh)
.SetBorder(Border.NO_BORDER)
.SetVerticalAlignment(VerticalAlignment.TOP);
tableObject.AddCell(cellLeft).AddCell(cellMiddle).AddCell(cellRight);
return Result;
}
这是v7.0.2中的错误,因为v7.0.1成功运行上面的代码......?我还检查了Table对象不是null,但异常告诉该对象可能为null ...这个修复的任何线索或解决方案......?
答案 0 :(得分:1)
不幸的是,这确实是7.0.2
中的一个错误,它与表的相对定位的错误处理有关,并且存在于Java和C#中。它已经修复,但修复程序仅在7.0.3
版本中可用。但是,您始终可以从Artifactory下载快照版本(在C#中也称为7.0.2.1
)。