Question

我尝试构建一个包含文本输入和按钮的公式当我按下按钮我想在下面的代码中显示一些消息

示例

if my first character is an A 
i want to display "GROUP1-1"

else if my first character is an B
i want to display "GROUP1-2"

else if my first character is an C
i want to display "GROUP1-3"  

if my second character is an F 
i want to display "GROUP2-1"

else if my my second character is an G
i want to display "GROUP2-2"

当我按下按钮时，这是我的代码程序工作，但总是有这个消息 “注意：未定义的索引：t在C：\ Program Files（x86）\ EasyPHP 2.0b1 \ www \ exercice \ test1 \ test1.php的第18,22,26,30,34行”

和程序工作

我使用Notepad ++ 和easyPHP

<html>
<head>
<meta charset="utf-8"/>
<title>
exercice 
</title>
</head>
<body>
<form action="" method="post">
decoder ces caracteres 
<input type = "text" name ="t" size="17"/>
<br>
<br>
<center>
<input type ="submit" name ="decoder" value="Decoder">
</center>
<?php
if($_GET['t'][0]=='A') {
echo "GROUP1-1"; 
}
else 
if($_GET['t'][0]=='B') {
echo "GROUP1-2"; 
}
else 
if($_GET['t'][0]=='C') {
echo "GROUP1-3"; 
}
if($_GET['t'][1]=='F') {
echo "GROUP2-1"; 
}
else 
if($_GET['t'][1]=='G') {
echo "GROUP2-2"; 
}
?>
</form>
</body>
</html>

Answer 1

您的表单操作设置为post，但您正在使用$_GET。将$_GET更改为$_POST。

<?php
if(!empty($_POST['t']) && $_POST['t']=='A') {
  echo "GROUP1-1"; 
} else if(!empty($_POST['t']) && $_POST['t']=='B') {
  echo "GROUP1-2"; 
} else if(!empty($_POST['t']) && $_POST['t']=='C') {
  echo "GROUP1-3"; 
} else if(!empty($_POST['t']) && $_POST['t']=='F') {
  echo "GROUP2-1"; 
} else if(!empty($_POST['t']) && $_POST['t']=='G') {
  echo "GROUP2-2"; 
}
?>

或者更好的解决方案是使用switch：

if(!empty($_POST['t'])) {
  switch($_POST['t']) {
    case 'A':
      echo "GROUP1-1";
      break;
    case 'B':
      echo "GROUP1-2";
      break;
    case 'C':
      echo "GROUP1-3";
      break;
    case 'F':
      echo "GROUP2-1";
      break;
    case 'G':
      echo "GROUP2-2";
      break;
    default:
      echo "Invalid Input";
      break;
  }
}

Answer 2

这就是我的意思，您还应该进行测试以了解表单是否已提交

if(isset($_POST['t']))
{
   if($_POST['t'][0]=='A')
      echo"GROUP1-1";
}

Decoder une chaine de caractere avec html，javascript，php

2 个答案: