Question

全日制学生的学费是每年12000美元。已经宣布未来5年每年的学费将增加2％。我如何编写一个c＃循环来计算未来5年每年2％的学费增长

到目前为止我的代码是..

private void button1_Click(object sender, EventArgs e)
    {
        string display;         
        double initialfee = 12000.00;
        double increase,newfee;
        double rate = 0.02;
        listBox1.Items.Clear();

        for (int year = 1; year <= 5; year++)
        {
            increase = initialfee * rate * year;
            newfee = increase + initialfee;


            display = "year " + year.ToString() + ": " + "  Amount " + "$" + newfee;

            listBox1.Items.Add(display);

Answer 1

你不需要乘以年份。试试这个

string display;         
double initialfee = 12000.00;
double increase=0,newfee;
double rate = 0.02;


for (int year = 1; year <= 5; year++)
{
    if(year>1)
    {
        increase = initialfee * rate;
    }

    initialfee = increase + initialfee;


    display = "year " + year.ToString() + ": " + "  Amount " + "$" + initialfee;
    Console.WriteLine(display);

}

输出：

year 1:   Amount $12000
year 2:   Amount $12240
year 3:   Amount $12484.8
year 4:   Amount $12734.496
year 5:   Amount $12989.18592

Answer 2

这是一个计算的解决方案。

private void button1_Click(object sender, EventArgs e)
{
    string display;         
    double initialfee = 12000.00;
    double increase,newfee;
    double rate = 0.02;
    listBox1.Items.Clear();

    for (int year = 1; year <= 5; year++)
    {
       newfee = initialfee + (initialfee * 2/100 * year);
       display = "year " + year.ToString() + ": " + "  Amount " + "$" + newfee;
    }
}

这个计算第一年为2％，明年为4％，依此类推。

如果每年需要增加2％的化合物，那么，

private void button1_Click(object sender, EventArgs e)
{
    string display;         
    double initialfee = 12000.00;
    double increase,newfee;
    double rate = 0.02;
    listBox1.Items.Clear();

    for (int year = 1; year <= 5; year++)
    {
      if(year == 1)
          newfee = initialfee;
      else
          newfee = newfee + (newfee * 2 / 100);

      display = "year " + year.ToString() + ": " + "  Amount " + "$" + newfee;
    }
}

希望这有帮助！

Answer 3

Linq 解决方案：

using System.Linq;

...

// Please, see separation:

// Model: here we define condition

// initial conditions  
double initialfee = 12000.00;
double rate = 0.02;
int years = 5;

// Business logic: here we obtain data

// please, notice formatting (here is C# 6.0 string interpolation) 
// which is easier to read and maintain then contructing string from chunks added.
var data = Enumerable
  .Range(1, years)
  .Select(year => $"Year {year}: Amount: {Math.Pow(1.0 + rate, year - 1) * initialfee:f2}")
  .ToArray();

// Representation: UI representation

// Add items in one go to prevent redrawing and blinking
listBox1.Items.AddRange(data);

结果是

Year 1: Amount: 12000.00
Year 2: Amount: 12240.00
Year 3: Amount: 12484.80
Year 4: Amount: 12734.50
Year 5: Amount: 12989.19

我知道，您正在寻找循环解决方案，但在真实世界中，我们通常更喜欢使用数据查询。

我如何编写一个c＃循环来计算未来5年每年增加2％的Tution

3 个答案: