Question

假设：

1bhk flat 200rupee maintenanceance

2bhk flat 400rupee维持费用

假设1 bhk用户支付给定日期的金额。

但如果用户未在指定日期支付金额，则自动将20％的额外费用添加到基本金额。

是否可以在Objective C中实现这一点？

Answer 1

这是非常简单的兄弟。以下代码适用于1BHK用户。

float oneBHKCharge=200;

float finalDue=0;

NSString *strDueDate = @"10-02-2017";
NSString *strPaidDate = @"10-02-2017";

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"dd-MM-yyyy"];
NSDate *dueDate = [dateFormatter dateFromString:strDueDate];
NSDate *paidDate = [dateFormatter dateFromString:strPaidDate];


NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
NSDateComponents *components = [gregorianCalendar components:NSCalendarUnitDay
                                                    fromDate:dueDate
                                                      toDate:paidDate
                                                     options:0];


if (components.day > 0)
{
    finalDue = oneBHKCharge + oneBHKCharge*0.2;
}
else
{
    finalDue = oneBHKCharge;
}

NSLog(@"%f",finalDue);

Answer 2

这里的代码我解决了这个话题。我在NSUserdefaults中存储了过期的日子。这是检查

- (NSNumber *)invoiceOverDue
{
   NSNumber *result;
   NSInteger dueDays = [[NSUserDefaults standardUserDefaults] integerForKey:VPPayDue];
  if ([[self dueTime] intValue] > dueDays) 
  {
    result = [NSNumber numberWithBool:YES];
  }

  else {
    result = [NSNumber numberWithBool:NO];
  }
  return result;
}

在这里，女巫的部分我计算了过期时间。

// DueTime calculation
-(NSNumber *)dueTime
{
// NSTimeInterval secondsPerDay = 24 * 60 * 60;
if ([[self invoiceStatus] intValue] > 1)
{
    return [NSNumber numberWithInt:0];
}

else {
    NSTimeInterval calculateTime = [[* Insert here the date of your invoice*] timeIntervalSinceNow];
    //DLog(@"dueTime bevor / 86400 :%f", calculateTime);
    calculateTime /= -86400;
    //DLog(@"dueTime :%f", calculateTime);
    int returnInt = [ConverterHelper numberRoundUp:calculateTime];

    return [NSNumber numberWithInt:returnInt];
}

}

查找两个给定日期之间的天数

2 个答案: