SQL返回有总和值

Question

我有一个检查组的查询，并确保它在2

下有超过1的值

SELECT `tile` FROM TFResults
GROUP BY `tile`
HAVING SUM(CASE WHEN `Place` < 2 THEN 1 ELSE 0 END)> 1 ;

我想要返回sum的值，但似乎无法让它工作

SELECT `tile`, thesum
FROM TFResults
GROUP BY `tile`
HAVING SUM(CASE WHEN `Place` < 2 THEN 1 ELSE 0 END) as thesum > 1 ;

Answer 1

您可以在select子句

中定义别名

SELECT tile, 
       SUM(CASE WHEN Place < 2 THEN 1 ELSE 0 END) as thesum
FROM TFResults
GROUP BY tile
HAVING thesum > 1

Answer 2

将sum语句移至select：

SELECT
    `tile`,
    SUM(CASE WHEN `Place` < 2 THEN 1 ELSE 0 END) AS thesum 
FROM TFResults
GROUP BY `tile`
HAVING thesum > 1 ;

Answer 3

首先，您需要将sum部分移动到select语句。如果您只需要检查一列，则使用if if CASE。检查下面

SELECT tile, SUM(if(Place < 2, 1, 0)) place_sum 
FROM TFResults
GROUP BY tile
HAVING place_sum > 1