Question

我正在尝试学习如何使用工作流程组件

在DefaultController.py中的这一行（远远低于）：

$service->apply($loginMessage, 'message_shown');

我收到了消息

Neither the property "marking" nor one of the methods "getMarking()", "marking()", "isMarking()", "hasMarking()", "__get()" exist and have public access in class "UserFlowBundle\Entity\LoginMessage".
500 Internal Server Error - NoSuchPropertyException

可能导致错误的原因是什么？我的代码与SFLive Example非常相似，我看不出有什么区别。

LoginModal.php

<?php

namespace UserFlowBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * LoginMessage
 *
 * @ORM\Table(name="login_message")
 * @ORM\Entity(repositoryClass="UserFlowBundle\Repository\LoginMessageRepository")
 */
class LoginMessage
{


    public function __construct($user)
    {
        $this->user = $user;
        $this->state = 'none';
    }

    /**
     * @var int
     *
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $id;

    /**
     * @var string
     *
     * @ORM\Column(name="state", type="string", length=255)
     */
    private $state;

    /**
     * @var string
     *
     * @ORM\Column(name="user", type="string", length=255, unique=true)
     */
    private $user;


    /**
     * Get id
     *
     * @return int
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * Set state
     *
     * @param string $state
     *
     * @return LoginMessage
     */
    public function setState($state)
    {
        $this->state = $state;

        return $this;
    }

    /**
     * Get state
     *
     * @return string
     */
    public function getState()
    {
        return $this->state;
    }

    /**
     * Set user
     *
     * @param string $user
     *
     * @return LoginMessage
     */
    public function setUser($user)
    {
        $this->user = $user;

        return $this;
    }

    /**
     * Get user
     *
     * @return string
     */
    public function getUser()
    {
        return $this->user;
    }
}

DefaultController.py

  <?php
    namespace UserFlowBundle\Controller;
    use Symfony\Bundle\FrameworkBundle\Controller\Controller;
    use Sensio\Bundle\FrameworkExtraBundle\Configuration\Method;
    use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
    use Symfony\Component\HttpFoundation\Request;
    /**
     * @Route("/userflow")
     */
    class DefaultController extends Controller
    {
        /**
         * @Route("/")
         */
        public function indexAction()
        {
            $user = $this->get('security.token_storage')->getToken()->getUser();
            return $this->render('UserFlowBundle:Default:index.html.twig', ['user'=>$user]);
        }

        /**
         * @Route("/apply-transition/", name="user_flow_apply_transition")
         * @Method("POST")
         */
        public function applyTransitionAction(Request $request)
        {
            try {
                $user = $this->get('security.token_storage')->getToken()->getUser();
                $em = $this->get('doctrine')->getManager();
                $repository = $em->getRepository('UserFlowBundle:LoginMessage');
                $loginMessage = $repository->findOneOrCreateByUser($user);
                $service = $this->get('state_machine.loginModal');
                $service->apply($loginMessage, 'message_shown');
                #$service->apply($loginMessage, $request->request->get('transition'));
                $this->get('doctrine')->getManager()->flush();
            } catch (ExceptionInterface $e) {
                $this->get('session')->getFlashBag()->add('danger', $e->getMessage());
            }
            return $this->redirect(
                $this->generateUrl('task_show', ['id' => 1])
            );
        }

    }

Answer 1

我对工作流程组件不太熟悉，但我对symfony非常熟悉。

在查看https://github.com/lyrixx/SFLive-Paris2016-Workflow/blob/master/src/AppBundle/Entity/Task.php后，我发现，您还没有声明方法getMarking和setMarking，这也是错误消息所说的内容。

我有根据的猜测是，工作流程组件需要某种标记来告诉它，实体处于哪种状态。

Answer 2

如Symfony文档所述：

marking_store选项的类型（默认值single_state）和参数（默认值 marking ）属性是可选的。如果省略，将使用其默认值。

如果state属性未命名为“ marking”，则可以这样配置它：

# config/packages/workflow.yaml
framework:
workflows:
    my_workflow:
        type: 'state_machine'
        marking_store:
            type: 'single_state'
            arguments:
                - 'myStateProperty'
        support:
            - App\Entity\MyEntity

Symfony Workflow Component Prolem ...标记不存在

2 个答案: