Question

我正在尝试使用此代码更新某些数据库值

public function updateImprovement($id, $improveId, $body) {

    //UPDATE ITC
  $update = ("UPDATE as_improvement SET value = :value WHERE id = :id");

  $statement = $this->db-> prepare($update);

    $statement -> bindValue( ":id", $id, PDO::PARAM_STR );
    $statement -> bindValue( ":value", $body, PDO::PARAM_STR );


    $statement -> execute();

    //UPDATE IMPROVE
    $update = ("UPDATE as_improve SET content_new = :content_new AND approved = 1 WHERE id = :improveId");

  $statement = $this->db-> prepare($update);


    $statement -> bindValue( ":improveId", $improveId, PDO::PARAM_STR );
    $statement -> bindValue( ":content_new", $body, PDO::PARAM_STR );



    $statement -> execute();

}

问题在于“content_new” - ＆gt; （content_new =：content_new）变量，因为没有它，sql语句就完美地执行了。我可以用两句话两次使用$ body吗？

Answer 1

您正在运行content_new = :content_new AND approved = 1

应该是：content_new = :content_new, approved = 1

但是，我已经为你做了一点回事：

public function updateImprovement($id, $improveId, $body) {

    //UPDATE ITC
    $update = ("UPDATE as_improvement SET value = ? WHERE id = ?");
    $statement = $this->db-> prepare($update);
    $statement->execute([$body, $id]);

    //UPDATE IMPROVE
    $update = ("UPDATE as_improve SET content_new = ?, approved = 1 WHERE id = ?");
    $statement = $this->db-> prepare($update);
    $statement->execute([$body, $improveId]);
}

使用pdo更新sql数据库

1 个答案: