Question

＆＃13;

function passWord() {
  var pass1 = prompt('Please Enter Your Password',' ');
  if (!pass1) {
    window.location.href = ('bad.html');
  }
  else if (pass1.toLowerCase() == "yep") {
    window.location.href = ('webpage.html');
    break;
  } 
  else {
    var pass2 = prompt('Password Incorrect','Password');
    if (!pass2) {
      window.location.href = ('bad.html');
    }
    else if (pass2.toLowerCase() == "yep") {
      window.location.href = ('webpage.html');
      break;
    } 
    else {
      var pass3 = prompt('Incorrect, last try','Password');
      if (!pass3) {
        window.location.href = ('bad.html');
      }
      else if (pass3.toLowerCase() == "yep") {
        window.location.href = ('webpage.html');
        break;
      } 
      else {
        window.location.href = ('bad.html');
      }
    }
  }
}
window.onload = passWord()

＆＃13;

我正在尝试创建一个脚本，以便它要求输入密码三次，如果它们都不正确，它会将您带到“坏”的＃34;页。但是，该脚本似乎不起作用。我不知道我的代码有什么问题...... 我不应该在其他地方有ifs和elses吗？

Answer 1

您只需要将break语句切换为return。一旦你想离开这个方法。 break用于保留循环块。

＆＃13;

function passWord() {
  var pass1 = prompt('Please Enter Your Password',' ');
  if (!pass1) {
    window.location.href = ('bad.html');
  }
  else if (pass1.toLowerCase() == "yep") {
    window.location.href = ('webpage.html');
    return;
  } 
  else {
    var pass2 = prompt('Password Incorrect','Password');
    if (!pass2) {
      window.location.href = ('bad.html');
    }
    else if (pass2.toLowerCase() == "yep") {
      window.location.href = ('webpage.html');
      return;
    } 
    else {
      var pass3 = prompt('Incorrect, last try','Password');
      if (!pass3) {
        window.location.href = ('bad.html');
      }
      else if (pass3.toLowerCase() == "yep") {
        window.location.href = ('webpage.html');
        return;
      } 
      else {
        window.location.href = ('bad.html');
      }
    }
  }
}
window.onload = passWord()

＆＃13;

Answer 2

    function passWord() {
    var pass1 = prompt('Please Enter Your Password', '');
    if (!pass1) {
        window.location.href = ('bad.html');
    }
    else if (pass1.toLowerCase() == "yep") {
        window.location.href = ('webpage.html');
        return;
    } 
    else {
        var pass2 = prompt('Password Incorrect', 'Password');
        if (!pass2) {
            window.location.href = ('bad.html');
        }
        else if (pass2.toLowerCase() == "yep") {
            window.location.href = ('webpage.html');
            return;
        } 
        else {
            var pass3 = prompt('Incorrect, last try', 'Password');
            if (!pass3) {
                window.location.href = ('bad.html');
            }
            else if (pass3.toLowerCase() == "yep") {
                window.location.href = ('webpage.html');
                return;
            } 
            else {
                window.location.href = ('bad.html');
            }
        }
    }
}

window.onload = function() {
    passWord();
}

我在这里丢失了你的缩进，但上面的代码看起来像你想要的效果。

代码未加载，因为您没有正确调用window.onload函数。由于“休息”，条件在被调用后无法正常工作。

Answer 3

我发现了自己，显然我不需要任何破坏标签。我删除了所有内容，现在我的代码正常运行感谢所有花时间回答我的问题的人，并且因为询问这样一个简单的错误而道歉

简单的密码javascript无法正常工作

3 个答案: