Question

嗨我有一个下拉菜单，它正在为搜索表单提供价值。搜索有两个标准。物业类别＆amp;属性子类别。选择两者时，搜索工作正常。物业类别有五个选项：空白，住宅，商业，工业，农业..我想构建查询，因此如果属性类别中的值为空，则应显示与住宅，商业，工业和农业相匹配的所有结果。目前留空是没有答案。

我尝试了两种方法，使用数组，然后构造mysql IN数组..但问题是如何搜索数组或mysql中的变量......

以下是html表单

<select class="searchpropertyinputs" name="property_category" id="property_category" onchange="subcategory('property_category', 'property_subcategory');">
    <option value="">Property Type</option>
    <option value="Residential">Residential</option>
    <option value="Commercial">Commercial</option>
    <option value="Industrial">Industrial</option>
    <option value="Agricultural">Agricultural</option>
</select>
</br>

<select class="searchpropertyinputs" name="property_subcategory" id="property_subcategory">
    <option value="">Property Subtype</option>
</select>
</br>

PHP

$property_category = ($_GET['property_category']);

$select = $con->prepare("SELECT * FROM tbl_property WHERE (property_category='$property_category' AND property_subcategory='$property_subcategory') LIMIT {$start}, {$perPage}");
$select->setFetchMode(PDO::FETCH_ASSOC);
$select->execute();

我正在尝试执行以下操作，但问题是如果选择了值，则它是一个变量，否则如果它是空白则它是一个数组..因此结构查询是个问题

if ($property_category == ""){
$myarray[1] = "'Residential'";
$myarray[2] = "'Commercial'";
$myarray[3] = "'Industrial'";
$myarray[4] = "'Agricultural'";
$property_category = implode(", ", $myarray);
}

$select = $con->prepare("SELECT * FROM tbl_property WHERE property_category IN ($property_category) LIMIT {$start}, {$perPage}");
$select->setFetchMode(PDO::FETCH_ASSOC);
$select->execute();
$count = $select->rowCount();

所需的结果是根据用户输入进行搜索，但如果用户没有选择任何内容（空白值），则给出列中存在的所有结果。

这不起作用，它没有给出任何结果

$select = $con->prepare(
"SELECT * FROM tbl_property 
WHERE property_category LIKE
    CASE WHEN '$property_category' = '' 
    THEN '%'
    ELSE '$property_category'
    END CASE
    LIMIT {$start}, {$perPage}");
$select->setFetchMode(PDO::FETCH_ASSOC);
$select->execute();
$count = $select->rowCount();

Answer 1

这似乎正在发挥作用

$search = array(
    "select" => "SELECT * FROM tbl_property",
    "where" => "WHERE property_category='$property_category'",
);

if (empty($property_category)) {
    unset($search["where"]);
}

$search = implode(' ', $search);

$select = $con->prepare($search);
$select->setFetchMode(PDO::FETCH_ASSOC);
$select->execute();
$count = $select->rowCount();

这似乎也在起作用

$search =
    "SELECT * FROM tbl_property " .
    (empty($property_category) ? "" : "WHERE property_category='$property_category' ");

$select = $con->prepare($search);
$select->setFetchMode(PDO::FETCH_ASSOC);
$select->execute();
$count = $select->rowCount();

现在的问题是，为什么我需要这么长时间来理解和做事......

Answer 2

试试这个：

$where = array();
$select_query = "SELECT * FROM tbl_property";
if (!empty($property_category)) {
    $where[] = "property_category='$property_category'";
}
$search_query = $select_query;
if (!empty($where)) {
    $search_query = $select_query . " Where " . implode(" ", $where);
} 

$result = $con->prepare($search_query);
$result->setFetchMode(PDO::FETCH_ASSOC);
$result->execute();
$count = $select->rowCount();

字段为空时返回所有结果

2 个答案: