Question

从日志文件中计算，衡量（计算）两个时间戳之间的时间间隔的最有效方法是什么？我知道Excel / Numbers / Refine中的愚蠢解决方案，但我正在寻找一个聪明的awk-oneliner。

实施例：带有自动门系统的电梯在n层楼上运行。

电梯打开了门：

Start Move to Work_position

电梯门是开着的：

End Move to Work_position

电梯关上了门

Start Move to Home_Position End Move to Home_Position

（准备好的）日志文件：

Elevator_021 logger:  2017-02-13 13:11:33.735 [MONITORING] CYL_A1; Floor_12 Door ;Start Move to Work_position  
Elevator_021 logger:  2017-02-13 13:11:34.800 [MONITORING] CYL_A1; Floor_12 Door ;End Move to Work_position  

Elevator_021 logger:  2017-02-13 13:26:12.893 [MONITORING] CYL_A1; Floor_12 Door ;Start Move to Home_Position  
Elevator_021 logger:  2017-02-13 13:26:13.898 [MONITORING] CYL_A1; Floor_12 Door ;End Move to Home_Position  

Elevator_021 logger:  2017-02-13 14:51:03.211 [MONITORING] CYL_A1; Floor_12 Door ;Start Move to Work_position  
Elevator_021 logger:  2017-02-13 14:51:04.276 [MONITORING] CYL_A1; Floor_12 Door ;End Move to Work_position

我正在寻找这样的输出：

Elevator_021 logger:  2017-02-13 13:11:33.735 [MONITORING] CYL_A1; Floor_12 Door ;Start Move to Work_position  
Elevator_021 logger:  2017-02-13 13:11:34.800 [MONITORING] CYL_A1; Floor_12 Door ;End Move to Work_position  
to Work 1065 ms  

Elevator_021 logger:  2017-02-13 13:26:12.893 [MONITORING] CYL_A1; Floor_12 Door ;Start Move to Home_Position  
Elevator_021 logger:  2017-02-13 13:26:13.898 [MONITORING] CYL_A1; Floor_12 Door ;End Move to Home_Position  
to Home 1005 ms  

Elevator_021 logger:  2017-02-13 14:51:03.211 [MONITORING] CYL_A1; Floor_12 Door ;Start Move to Work_position  
Elevator_021 logger:  2017-02-13 14:51:04.276 [MONITORING] CYL_A1; Floor_12 Door ;End Move to Work_position  
to Work 3976 ms

Answer 1

您可以使用gawk执行以下操作：

awk 'function dtime(s) {
         x=match($0, /([0-9]{4}-[0-9]{2}-[0-9]{2}\s[0-9:]+)(\.[0-9]+).*([0-9]{4}-[0-9]{2}-[0-9]{2}\s[0-9:]+)(\.[0-9]+).*(to \w+)_/, arr)
         if (x) {
              s1=arr[1]
              s2=arr[3]
              gsub(/[-:]/, " ", s1)
              gsub(/[-:]/, " ", s2)
              t1=mktime(s1)+arr[2]
              t2=mktime(s2)+arr[4]
              return arr[5] " " (t2-t1)*1000 " ms"
         }
         else
              return ""
         }
BEGIN   {RS=ORS="\n\n"} 
        {print $0 " -> " dtime($0) }' file

打印：

Elevator_021 logger：2017-02-13 13：11：33.735 [MONITORING] CYL_A1; Floor_12门;开始移动到Work_position Elevator_021 logger：2017-02-13 13：11：34.800 [MONITORING] CYL_A1; Floor_12 Door; End Move to Work_position - ＆gt;工作1065毫秒

Elevator_021 logger：2017-02-13 13：26：12.893 [MONITORING] CYL_A1; Floor_12门;开始移动到Home_Position Elevator_021 logger：2017-02-13 13：26：13.898 [MONITORING] CYL_A1; Floor_12 Door; End Move to Home_Position - ＆gt;回家1005毫秒

Elevator_021 logger：2017-02-13 14：51：03.211 [MONITORING] CYL_A1; Floor_12门;开始移动到Work_position Elevator_021 logger：2017-02-13 14：51：04.276 [MONITORING] CYL_A1; Floor_12 Door; End Move to Work_position - ＆gt;工作1065毫秒

什么是测量两个时间戳之间的时间跨度的最佳方法

1 个答案: