在swift中消除数组中每个字符串的不需要的字符

Question

我有一个名为coordinateArray的数组，它保存着这些数据：

["(19.452187074041884", " -99.1457748413086)", "(19.443769985032485", " -99.14852142333984)", "(19.443446242121073", " -99.13787841796875)", "(19.450244707639662", " -99.13822174072266)"]
["(19.407780723677718", " -99.18417591514299)", "(19.400373302640162", " -99.18473381461808)", "(19.400049473260434", " -99.18039936485002)", "(19.405433052977592", " -99.17838234367082)"]
["(19.4022042123319", " -99.1457748413086)", "(19.401070819438004", " -99.16139602661133)", "(19.39184146912981", " -99.16268348693848)", "(19.389736456288546", " -99.14706230163574)"]
["(19.42114689571205", " -99.17375564575195)", "(19.425598915444077", " -99.15392875671387)", "(19.414913863184566", " -99.15470123291016)", "(19.41264724664359", " -99.16594505310059)", "(19.412890099927345", " -99.16766166687012)"]

我需要从每个坐标中删除括号

如何在Swift 3.0中执行此操作？

我试图这样做

let coordinateArray = coor.components(separatedBy: ",")                    
                    var coordinateArrayF = [String]()
                    for coordinate in coordinateArray {
                        let coordinatevar = coordinate.replacingOccurrences(of: "()", with: "")
                        coordinateArrayF.append(coordinatevar)
                    }

但它不起作用我做错了什么？

Answer 1

功能编程是你的朋友！

var data = ["(19.452187074041884", " -99.1457748413086)", "(19.443769985032485", " -99.14852142333984)", "(19.443446242121073", " -99.13787841796875)", "(19.450244707639662", " -99.13822174072266)"]

let cleanData = data.map { 
     item in item.replacingOccurrences(of: "(", with: "")
}