我试图用谷歌找到这个答案,但没有任何结果。我正在将应用程序从Qt4转换为Qt5。这个应用程序在Qt4中完美编译但是当我尝试编译Qt5现在它给了我这个权限错误。由于这个类的状态在两个版本中都受到保护,因此我很难理解需要更改的内容。
这个编译问题已经在一些不同的Ubuntu安装(包括wsl)上复制,但我还没有在Fedora中尝试过。
这是班级的一个子集
#include <QWidget>
#include <QEvent>
#include <QTableWidget>
#include <QItemDelegate>
#include <QModelIndex>
#include <QSize>
#include <qdialog.h>
#include <qcombobox.h>
#include "ui_pegs_page.h"
#include <string>
class EGS_ConfigReader;
class QProcess;
class PEGS_RunOutput;
class QTableWidget;
struct Element {
int Z;
std::string symbol;
float aw;
float Iev;
float rho;
};
const int n_element = 100;
extern Element element_data[];
class TableEventHandler : public QObject {
Q_OBJECT
public:
TableEventHandler(QTableWidget *parent);
protected:
bool eventFilter(QObject *o, QEvent *e);
private:
QStringList itemCopy;
QList<QTableWidgetSelectionRange> copyRange;
};
编辑:
这是有问题的方法。
TableEventHandler::TableEventHandler(QTableWidget *parent) :
QObject(parent) {
if( parent == 0 )
qFatal("TableEventHandler::TableEventHandler: parent can not be null!");
}
bool TableEventHandler::eventFilter(QObject *o, QEvent *e) {
if( !o ) qWarning("TableEventHandler::eventFilter called with 0 object?");
if( QString(o->metaObject()->className()) != tr("QTableWidget") ) {
#ifdef EI_DEBUG
qDebug("Only QTableWidget objects accepted! Returning!");
#endif
return false;
}
QTableWidget *to = (QTableWidget *)o;
if( e->type() == QEvent::KeyPress ) {
QKeyEvent *ke = (QKeyEvent*)e;
if(ke->matches(QKeySequence::Copy) ){
QString cellText; itemCopy.clear(); copyRange.clear();
QList<QTableWidgetSelectionRange> ts = to->selectedRanges();
if(!ts.isEmpty()) {
for ( int irow = ts.first().topRow(); irow <= ts.first().bottomRow(); irow++){
for ( int icol = ts.first().leftColumn(); icol <= ts.first().rightColumn(); icol++){
QTableWidgetItem *w = to->item(irow,icol);
if(w) cellText = w->text();
if ( !cellText.isEmpty() ){
itemCopy << cellText;
}
else
itemCopy << " ";
}
}
copyRange = ts;
//cout << itemCopy.join(", ").toLatin1().data() << endl;
}
else {
QTableWidgetItem *w = to->item(to->currentRow(), to->currentColumn());
if (w) cellText = w->text();
if ( !cellText.isEmpty() )
itemCopy << cellText;
else itemCopy << "";
}
return true;
}
else if(ke->matches(QKeySequence::Paste) && !itemCopy.isEmpty() && !copyRange.isEmpty()){
QList<QTableWidgetSelectionRange> cs = to->selectedRanges();
int top = cs.first().topRow(), left = cs.first().leftColumn(), icount = 0;
QTableWidgetSelectionRange ts = QTableWidgetSelectionRange(
top , left,
top + copyRange.first().rowCount()-1,
left + copyRange.first().columnCount()-1);
for ( int irow = ts.topRow(); irow <= ts.bottomRow(); irow++){
for ( int icol = ts.leftColumn(); icol <= ts.rightColumn(); icol++){
if ( ++icount <= itemCopy.size() )
to->setItem(irow, icol, new QTableWidgetItem(itemCopy[icount-1]));
to->setItem(irow, icol, new QTableWidgetItem(itemCopy[icount-1]));
}
}
return true;
}
else if(ke->matches(QKeySequence::Cut) ){
QString cellText; itemCopy.clear(); copyRange.clear();
QList<QTableWidgetSelectionRange> ts = to->selectedRanges();
if(!ts.isEmpty()) {
for (int irow = ts.first().topRow(); irow <= ts.first().bottomRow(); irow++) {
for(int icol = ts.first().leftColumn(); icol <= ts.first().rightColumn(); icol++) {
QTableWidgetItem *w = to->item(irow,icol);
if(w) cellText = w->text();
if ( !cellText.isEmpty() ){
itemCopy << cellText;
}
else
itemCopy << "";
to->setItem(irow,icol,0);
}
}
copyRange = ts;
//cout << itemCopy.join(", ").toLatin1().data() << endl;
}
return true;
}
else if(ke->matches(QKeySequence::Delete) ){
QList<QTableWidgetSelectionRange> ts = to->selectedRanges();
if(!ts.isEmpty()) {
for (int irow = ts.first().topRow(); irow <= ts.first().bottomRow(); irow++) {
for(int icol = ts.first().leftColumn(); icol <= ts.first().rightColumn(); icol++) {
to->setItem(irow,icol,0);
}
}
}
return true;
}
else
to->eventFilter(o, e);
}
return false;
}
答案 0 :(得分:0)
您正在访问受保护的QAbstractScrollArea::eventFilter(QObject*, QEvent*)
方法
QAbstractScrollArea
(最有可能)的类的方法,或QAbstractScrollArea
的朋友(不太可能),或QAbstractScrollArea
的朋友(不太可能)。请注意,TableEventHandler
直接从QObject
继承,而不是从QAbstractScrollArea
继承。因此,如果您尝试从QAbstractScrollArea::eventFilter(QObject*, QEvent*)
的其中一种方法调用TableEventHandler
,则会出现该错误。
编辑:查看已修改的答案,我发现您正在调用
to->eventFilter(o, e);
TableEventHandler::eventFilter(QObject *o, QEvent *e)
QTableWidget *to = (QTableWidget *)o;
中的。程序员可能意味着TableEventHandler::eventFilter
不要在那时过滤相应的事件。然后,该方法应返回false
以将控制权传递给稍后在该对象上安装的任何其他事件过滤器。