Question

我的json文件有点问题，我要做的是从我的json文件中获取特定对象，所以在上面这个json我添加这个参数 stream_id = 并且例如，我添加此ID stream_id = 200 它应该只显示具有该ID的对象，所以要更清楚它应该显示 id：200，name：Ravi Tamada，email：ravi @ gmail .com 等等，用PHP，谢谢

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  <script>window.Polymer = {dom: 'shadow', lazyRegister: 'max', useNativeCSSProperties: true};</script>
  <base href="https://polygit.org/polymer+1.7.1/components/">
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  <link rel="import" href="polymer/polymer.html">
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<body>
  <x-foo></x-foo>

  <dom-module id="x-foo">
    <template>
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        p {
          --test: brown;
          color: var(--test);
        }
      </style>
      <p>Hello world</p>
    </template>
  </dom-module>
</body>

Answer 1

您可以遍历您的JSON并查找您需要的ID。就这么简单。

<?php
$json = /* your json */;
$array = json_decode($json, true);

$result = getInfo(200, $array);

function getInfo($id, $array) {
    foreach($array AS $index=>$json) {
        if($json['id'] == $id) {
            return $json;
        }
    }
}

Answer 2

可能你可以使用带有$ assoc = true的json_decode（此选项将json转换为数组，甚至转换为嵌套数组），然后遍历数组以找到所需的元素。

Answer 3

您应该能够使用如下所示的简单js / jquery函数循环访问JSON，您只需传递指定的id。

function getJsonById(id){
var json = {
        "contacts": [
            {
                    "id": "200",
                    "name": "Ravi Tamada",
                    "email": "ravi@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",
                    "url": "http://149.202.196.143:8000/live/djemal/djemal/592.ts"
            },
            {
                    "id": "201",
                    "name": "Johnny Depp",
                    "email": "johnny_depp@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",
                    "url":"http://149.202.196.143:8000/live/djemal/djemal/592.ts" 
            },
            {
                    "id": "202",
                    "name": "Leonardo Dicaprio",
                    "email": "leonardo_dicaprio@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",


    "url":"http://149.202.196.143:8000/live/djemal/djemal/592.ts" 
            }
        ]
    };

var l= json['contacts'].length;
var c = 0;
while(c<l){
  if(json['contacts'][c]['id']==id){
    console.log(json['contacts'][c]);
     return json['contacts'][c];
  } 
  c++;
}
}
return "";
});

从特定的Id JSON获取特定对象

3 个答案: