Question

我想在我的左连接中添加一些额外的过滤器，但我不知道如何善意帮助我。还告诉我如何在Eloquent中进行此查询。我的查询如下：

select * from `users`
join `halls` on `halls`.`user_id` = `users`.`id` 
left join `bookings` on `bookings`.`hall_id` = `halls`.`id` AND month(`bookings`.`date`) = 2 and day(`bookings`.`date`) = 4 and year(`bookings`.`date`) = 2017
join `user_role` on `user_role`.`user_id` = `users`.`id` 
join `roles` on `roles`.`id` = `user_role`.`role_id` 
where 
    `roles`.`id` = 2 AND

     (`bookings`.`id` is null OR `bookings`.`status` = 0 )

     group by users.id

用户和角色有多对多关系，用户和大厅一对多和大厅和预订也有一对多的关系用户模型关系

/**
     * Many-to-Many relations with Role.
     *
     * @return \Illuminate\Database\Eloquent\Relations\BelongsToMany
     */
public function roles(){
    return $this->belongsToMany(Role::class, 'user_role', 'user_id', 'role_id')->select('roles.name');
}
/**
 * One-to-Many relations with halls.
 *
 * @return \Illuminate\Database\Eloquent\Relations\hasMany
 */
public function halls(){
    return $this->hasMany(Hall::class);
}

霍尔模型关系

public function user(){

    return $this->belongsTo(User::class, 'user_id', 'id');
}
public  function  bookings(){
    return $this->hasMany(Booking::class);
}

预订模型实现

public function hall(){
    return $this->belongsTo(Hall::class)->distinct();
}

Answer 1

我不知道你为什么要使用group by而没有任何聚合函数。您的ORM如下所示

Users::join('halls', 'users.id', '=', 'halls.user_id')
leftJoin('bookings', function($join){
    $join->on('halls.id', '=', 'bookings.hall_id');
    $join->on(DB::raw('month(`bookings`.`date`) = 2 and day(`bookings`.`date`) = 4 and year(`bookings`.`date`) = 2017'));

})
->join('user_role', 'users.id', '=', 'user_role.user_id')
->join('roles', 'roles.id', '=', 'user_role.role_id')
->whereRaw('where 
    `roles`.`id` = 2 AND

     (`bookings`.`id` is null OR `bookings`.`status` = 0 )')->get();

在laravel 5.3中以简单和雄辩的方式加入

1 个答案: