具有子类别的列表的ArrayList方法

Question

这是我现在正在使用的代码：

    public void onDataChange(DataSnapshot dataSnapshot) {

            for (DataSnapshot moviecatlog: dataSnapshot.getChildren()) {
                Actors =  (String) moviecatlog.child("Actors").getValue();
                Description = (String) moviecatlog.child("Description").getValue();
                Director = (String) moviecatlog.child("Director").getValue();
                Genre = (String) moviecatlog.child("Genre").getValue();
                Published = (String) moviecatlog.child("Published").getValue();
                MovieUrl = (String) moviecatlog.child("MovieUrl").getValue();
                Status = (String) moviecatlog.child("Status").getValue();
                ThumbUrl = (String) moviecatlog.child("ThumbUrl").getValue();
                Title = (String) moviecatlog.child("Title").getValue();
                id = (String) moviecatlog.child("id").getValue();


//                    recyclerView.setAdapter(new RecyclerViewAdapter(moviecatlog));

                ar = new ArrayList<String>();

                ar.add(Actors);
                ar.add(Description);
                ar.add(Director);
                ar.add(Genre);
                ar.add(MovieUrl);
                ar.add(Published);
                ar.add(Status);
                ar.add(ThumbUrl);
                ar.add(Title);
                ar.add(id);

                recyclerView.setAdapter(new RecyclerViewAdapter(ar));

如何将数据放入ArrayList？现在，我只能将所有数据放在一起，但最后，它只显示ArrayList中最后一项的属性。

Answer 1

   Arraylist actor=new Arraylist ();
        notification = new ArrayList<HashMap<String, String>>();
        notification1 = new ArrayList<HashMap<String, String>>();

        HashMap<String, String> list = new HashMap<String, String>;
          actoredata[]={om puri ,raj,};
          directore[]={mahesh bhatt,payrelal};
          for(i=0;i<actoredatalenth(),i++){


            list.put("actor", actore[i])));
        notification.add(list);
            }
            actore.add(notification);
             for(i=0;i<directorelenth(),i++){


            list.put("actor", directore[i])));
        notification.add(list);
            }actore.add(notification);