Question

这是我的代码，我试图遍历这个json，所以我想做的是当isset($_GET['latest=1']))它应该从上面的json显示一个对象时，如果latest = 15它应该显示15个对象，我怎么能这样做

    <?php
header('Content-Type: application/json');
if(isset($_GET['latest']))
echo 
'
    {
        "contacts": [
            {
                    "id": "c200",
                    "name": "Ravi Tamada",
                    "email": "ravi@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",
                    "url": "http://149.202.196.143:8000/live/djemal/djemal/592.ts"
            },
            {
                    "id": "c201",
                    "name": "Johnny Depp",
                    "email": "johnny_depp@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",
                    "url":"http://149.202.196.143:8000/live/djemal/djemal/592.ts" 
            },
            {
                    "id": "c202",
                    "name": "Leonardo Dicaprio",
                    "email": "leonardo_dicaprio@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",


    "url":"http://149.202.196.143:8000/live/djemal/djemal/592.ts" 
            }
        ]
    }
';

Answer 1

我建议您将数据转换为数组，然后在对数据进行排序后重新编码。

以下可能有一些帮助：

<强> URL：

http://localhost/index.php?latest=2

代码 - 第1部分：

这是上面的JSON数据的副本。

$json = ' {
        "contacts": [
            {
                    "id": "c200",
                    "name": "Ravi Tamada",
                    "email": "ravi@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",
                    "url": "http://149.202.196.143:8000/live/djemal/djemal/592.ts"
            },
            {
                    "id": "c201",
                    "name": "Johnny Depp",
                    "email": "johnny_depp@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",
                    "url":"http://149.202.196.143:8000/live/djemal/djemal/592.ts" 
            },
            {
                    "id": "c202",
                    "name": "Leonardo Dicaprio",
                    "email": "leonardo_dicaprio@gmail.com",
                    "address": "xx-xx-xxxx,x - street, x - country",
                    "gender" : "male",


    "url":"http://149.202.196.143:8000/live/djemal/djemal/592.ts" 
            }
        ]
    }';

代码 - 第2部分：

$count = (isset($_GET['latest']) && filter_var($_GET['latest'], FILTER_VALIDATE_INT) && $_GET['latest'] >= 1) ? $_GET['latest'] : 1; //To ensure the GET is an INT and set a default value of 1.
$output = json_decode($json, TRUE); //Convert to array
$newArr = []; //Placeholder for new array

for($i=0; $i < $count; $i++) { //Dependent on value (1 being default) 

   if(isset($output['contacts'][$i])) { //Just incase you get an undefined index issue

       $newArr[] = $output['contacts'][$i]; 

   } else {

       break; //Break Loop if undefined
   }
}     

echo json_encode($newArr); //Finally output new array as JSON

输出（值为2）：

[{
    "id": "c200",
    "name": "Ravi Tamada",
    "email": "ravi@gmail.com",
    "address": "xx-xx-xxxx,x - street, x - country",
    "gender": "male",
    "url": "http:\/\/149.202.196.143:8000\/live\/djemal\/djemal\/592.ts"
}, {
    "id": "c201",
    "name": "Johnny Depp",
    "email": "johnny_depp@gmail.com",
    "address": "xx-xx-xxxx,x - street, x - country",
    "gender": "male",
    "url": "http:\/\/149.202.196.143:8000\/live\/djemal\/djemal\/592.ts"
}]

加了： 还添加了一个中断，以防他们要求您的数组中未定义的值。

注意：

速记三元仅适用于PHP 5.3，所以我怀疑你的错误与此有关。 PHP Shorthand ternary operator "?:" Parse error unexpected ":"

循环通过json对象php

1 个答案: