Question

我正在寻找一个python模块或一些现有的python代码，可用于包装使用＆＃34;＆gt;＆＃34;行前缀表示引用的文本（参见下面的示例）。

我知道我可以使用python textwrap 模块来包装文本段落。但是，该模块并不了解这种引用前缀。

我知道如何编写将执行此文本包装的例程，并且我不寻求有关如何编写它的建议。相反，我想知道是否有人知道已经存在的任何python代码或python模块，并且已经能够在电子邮件类型的引用文本上执行这种包装。

我一直在寻找，但我在python中找不到任何东西。

我只是不想重新发明轮子＆＃34;如果这样的事情已经写好了。

以下是我想要执行的文字换行的示例。假设我有以下来自假设电子邮件的文本：

Abc defg hijk lmnop.

Mary had a little lamb.
Her fleas were white as snow,

> Now is the time for all good men to come to the aid of their party.
>
> The quick
> brown fox jumped over the lazy sleeping dog.

>> When in the Course of human
>> events it
>> becomes necessary for one people to dissolve the political
>> bands
>> which have
>> connected them ...
      and everywhere that Mary went,
      her fleas were sure to go
      ... and to reproduce.
> What do you mean by this?
>> with another
>> and to assume among
>> the powers of the earth ...
> Doo wah diddy, diddy dum, diddy doo.
>> Text text text text text text text text text text text text text text text text text text text text text text text text text text text.

假设我想在第52列换行，结果文本应如下所示：

Abc defg hijk lmnop.

Mary had a little lamb. Her fleas were white as
snow,

> Now is the time for all good men to come to the
> aid of their party.
>
> The quick brown fox jumped over the lazy sleeping
> dog.

>> When in the Course of human events it becomes
>> necessary for one people to dissolve the
>> political bands which have connected them ...
      and everywhere that Mary went, her fleas were
      sure to go ... and to reproduce.
> What do you mean by this?
>> with another and to assume among the powers of
>> the earth ...
> Doo wah diddy, diddy dum, diddy doo.
>> Text text text text text text text text text text
>> text text text text text text text text text text
>> text text text text text text text.

感谢您对现有python代码的任何引用。

如果不存在这样的事情并且＃34;在野外＆＃34;，我会写下这个并在此处发布我的代码。

非常感谢。

Answer 1

我无法找到包含此类引用文本的现有代码，所以这里是我编写的代码。它使用 re 和 textwrap 模块。

我将代码分解为＆＃34;段落＆＃34;基于初始引号或缩进字符的数量。然后我使用 textwrap 来打包每个＆＃34;段落＃34;从每行中删除引用或缩进前缀。在换行之后，我将前缀重新添加到＆＃34;段落＆＃34;。

的每一行

有一天，我会清理代码并使其更加优雅，但至少它似乎工作得很好。

import re
import textwrap
def wrapemail(text, wrap=72):
    if not text:
        return ''
    prefix      = None
    prev_prefix = None
    paragraph   = []
    paragraphs  = []
    for line in text.rstrip().split('\n'):
        line = line.rstrip()
        m = wrapemail.qprefixpat.search(line)
        if m:
            prefix = wrapemail.whitepat.sub('', m.group(1))
            text   = m.group(2)
            if text and wrapemail.whitepat.search(text[0]):
                prefix += text[0]
                text    = text[1:]
        else:
            m = wrapemail.wprefixpat.search(line)
            if m:
                prefix = m.group(1)
                text   = m.group(2)
            else:
                prefix = ''
                text   = line
        if not text:
            if paragraph and prev_prefix is not None:
                paragraphs.append((prev_prefix, paragraph))
            paragraphs.append((prefix, ['']))
            prev_prefix = None
            paragraph   = []
        elif prefix != prev_prefix:
            if paragraph and prev_prefix is not None:
                paragraphs.append((prev_prefix, paragraph))
            prev_prefix = prefix
            paragraph   = []
        paragraph.append(text)
    if paragraph and prefix is not None:
        paragraphs.append((prefix, paragraph))
    result = ''
    for paragraph in paragraphs:
        prefix = paragraph[0]
        text   = '\n'.join(paragraph[1]).rstrip()
        wraplen = wrap - len(prefix)
        if wraplen < 1:
            result += '{}{}\n'.format(prefix, text)
        elif text:
            for line in textwrap.wrap(text, wraplen):
                result += '{}{}\n'.format(prefix, line.rstrip())
        else:
            result += '{}\n'.format(prefix)
    return result
wrapemail.qprefixpat = re.compile(r'^([\s>]*>)([^>]*)$')
wrapemail.wprefixpat = re.compile(r'^(\s+)(\S.*)?$')
wrapemail.whitepat   = re.compile(r'\s')

将原始邮件中的文字提供给它，并使用＆＃39; wrap＆＃39;指定为52确实会产生我在上面指定的输出。

随意改进或窃取它。：）

python：用于包装通过电子邮件约定引用的文本的模块？

1 个答案: