Question

我正在构建一个脚本来运行重复的测试，每个测试都有一个日志文件，该文件将被读取并编译成电子表格。

每个文件和行的数量将根据时间和所需的迭代而变化。我有一个基本脚本，逐行读取一个文件，并将数据粘贴到连续行的单独的Excel文档中。

from openpyxl import load_workbook
from Test_Parameters import Results_Name
from Downstream import Log_Angle

wb = load_workbook(filename= Results_Name +'.xlsm', read_only=False, keep_vba=True)
ws7 = wb['timeData']

FILE = open('0_Downstream.txt', 'r+')
line = FILE.readline()
N = '2'


while line !="":
    print(line)
    ws7['A'+N] = line
    line = FILE.readline()
        N = float(N)
        N = (N+1)
        N = "%g" % N
    wb.save(Results_Name+'.xlsm')

    FILE.close()

我需要能够让它循环遍历同一目录中的多个文件，并将结果放在一个单独的列中，而不是最后一个。与下表相似：Excel Layout

感谢您的帮助。

Answer 1

import os
cwd = os.getcwd()

for filename in os.listdir(cwd):
    if filename.endswith(".txt"):
        with open('%s\\%s' % (cwd, filename), 'r+') as file:
            [DO STUFF]

上面的代码允许您迭代当前工作目录中的多个文件（指定类型）。

这有帮助吗？

Answer 2

我正在和Luke一样思考（只是打了一段时间）：

from openpyxl import load_workbook
from Test_Parameters import Results_Name
from Downstream import Log_Angle
import os



def good_name():
    wb = load_workbook(filename=Results_Name + '.xlsm', read_only=False, keep_vba=True)
    ws7 = wb['timeData']

    for path in os.listdir('dir_path'):
        # You can use glob here if you have other extensions than .txt
        ws = load_sheet(path, ws7)
    wb.save(Results_Name + '.xlsm')

def load_sheet(file_path, ws):
    with open(file_path, 'r+') as FILE:
        # This context manager is a cleaner way to open/close our file handle
        line = FILE.readline()
        N = '2'
        while line !="":
            print(line)
            ws['A'+N] = line
            line = FILE.readline()
            N = float(N)
            N = (N+1)
            N = "%g" % N
    return ws

Answer 3

请勿使用ws['A'+N]进行编程访问。

我认为以下内容可能与您想要的相近：

col_idx = ws.max_column + 1
for row_idx, line in enumerate(file, 1):
    if line == "":
        break
    ws.cell(row=row_idx, col=col_idx, value=line)
wb.save(…)

Answer 4

此示例读取test / txt
为每个文件使用新列
将文件名分配给第1行

追加所有阅读行，从第2行开始

# List all files in test/txt'
dirName = os.path.join('test', 'txt')

for column,fname in enumerate(os.listdir(dirName),1):
  # Column Title = Filename
  ws.cell(row=1, column=column, value=fname)

  # My Sample Text files are utf-8 encoded
  with io.open( os.path.join(dirName, fname),'r', encoding='utf8') as fh:
    # Column Data begins on Row 2
    for row,line in enumerate(fh,2):
      ws.cell(row=row, column=column, value=line)
  #end with = closing fh
#end for

使用Python测试：3.4.2 - openpyxl：2.4.1 - LibreOffice：4.3.3.2 *

如何逐行读取多个文本文件并在每个文件后发送到excel移动到新列？

4 个答案: