Question

遵循BroadcastHub的示例，可以动态生成监听同一生产者的工作者。但是这个产卵必须在代码中明确地完成。我想知道它是否可以编码为流中事件的反应。

在下面的例子中，我希望在收到＆＃34; Spawn＆＃34;之后产生2个以上的工作人员。 spawns流中的消息。有可能吗？

package com.example

import akka.actor.ActorSystem
import akka.stream.ActorMaterializer
import akka.stream.scaladsl.{BroadcastHub, Flow, Keep, Sink, Source}

import scala.concurrent.duration._

object TestApp extends App {
  implicit val system = ActorSystem("system")
  implicit val materializer = ActorMaterializer()

  val ticks = Source.tick(0.second, 1.second, "Tick").take(10)

  val broadcaster = ticks.toMat(BroadcastHub.sink(bufferSize = 16))(Keep.right).run()

  def prefixFlow(tag:String) = Flow[String].map(_ + s" from $tag").to(Sink.foreach(println))

  // Print out messages from the producer in two independent consumers
  broadcaster.runWith(prefixFlow("1"))
  broadcaster.runWith(prefixFlow("2"))

  // Is it possible to spawn more flows based on another stream?
  val spawns = Source.tick(2.second, 3.second, "Spawn").take(2)
  // spawns.foreach(broadcaster.runWith(prefixFlow("XXX"))
}

Answer 1

在您的具体示例中，您是否可以寻找简单的map？

val spawns = Source
  .tick(2.second, 3.second, "Spawn")
  .take(2)
  .map(_ ⇒ broadcaster.runWith(prefixFlow("XXX")))
  .runWith(Sink.ignore)

是否有可能根据另一个流在Akka-Streams中生成Flow？

1 个答案: