Postgres获取列组中至少有一个特定值的行由另一列

Question

我有一个sql命令：

select location,status,total from my_table

此回报：

location - status - total
city a - active - 3
city a - pending - 2
city a - cancel - 4
city b - pending - 4
city b - cancel - 4
city c - active - 2
city c - cancel - 6

我如何只返回城市中至少有一次状态有效并且总＆gt; = 1的行？

所以，我想回来：

    location - status - total
    city a - active - 3
    city a - pending - 2
    city a - cancel - 4
    city c - active - 2
    city c - cancel - 6

正如您所注意到我不想返回城市b因为它没有至少有一次活动状态且总计> = 1。

Answer 1

select location,status,total from my_table
where location in (
    select location from my_table
    where status = 'active'
        and total >= 1
    )