Question

我正在尝试创建一个简单的程序，当你按住'w'时它会继续使用forward ()，但是当你放手时，它会使用stop()停止电机。目前，我只能在按下'w'时继续前进，只在按下另一个键时停止。这是我的代码

#!/usr/bin/env python3
 # so that script can be run from Brickman

 import termios, tty, sys, time
 from ev3dev.ev3 import *

 # attach large motors to ports B and C, medium motor to port A
 motor_left = LargeMotor('outA')
 motor_right = LargeMotor('outD')
 motor_a = MediumMotor('outC')

 #==============================================

 def getch():
     fd = sys.stdin.fileno()
     old_settings = termios.tcgetattr(fd)
     tty.setcbreak(fd)
     ch = sys.stdin.read(1)
     termios.tcsetattr(fd, termios.TCSADRAIN, old_settings)

     return ch

 #==============================================

 def fire():
    motor_a.run_timed(time_sp=3000, speed_sp=600)

 #==============================================

 def forward():
    motor_left.run_forever(speed_sp=1050)
    motor_right.run_forever(speed_sp=1050)

 #==============================================

 def back():
    motor_left.run_forever(speed_sp=-1050)
    motor_right.run_forever(speed_sp=-1050)

 #==============================================

 def left():
    motor_left.run_forever(speed_sp=-1050)
    motor_right.run_forever(speed_sp=1050)

 #==============================================

 def right():
    motor_left.run_forever(speed_sp=1050)
    motor_right.run_forever(speed_sp=-1050)

 #==============================================

 def stop():
    motor_left.run_forever(speed_sp=0)
    motor_right.run_forever(speed_sp=0)

 #==============================================

 print("ready")
    k = getch()
    print(k)
    if k == 'w':
       forward()
    if k == 's':
       back()
    if k == 'a':
       left()
    if k == 'd':
       right()
    if k == 'f':
       fire()
    if k == ' ':
       stop()
    if k == 'q':
       stop()
       exit()

关于如何使它成为stop（）的任何想法在'w'未被按下时运行？

Answer 1

您可以使用pygame的KEYUP和KEYDOWN功能。以下是使用pygame的代码片段：

.index

如何在按下键时才运行python函数？

1 个答案: