Question

我有一个Activity，它将一个项添加到创建的数据库中。我可以通过查询数据库来检索这个添加的项目。我想知道为什么，每当我尝试检索与该行关联的主键整数时，我的应用程序崩溃了？

这是我的DB合同类。它实现了BaseColumns，它会自动为我创建一个_ID变量。

    public static class FoodList implements BaseColumns {

    public static final Uri CONTENT_URI = BASE_CONTENT_URI.buildUpon().appendPath(PATH).build();
    public static final String TABLE_NAME = "food_table";
    public static final String ITEM_NAME = "item";
}

这是我的数据库类：

public class FoodDatabase {
private SQLiteDatabase db;
private DatabaseHelper databaseHelper;
private Context context;
public static final int DB_VERSION = 2;
public static final String DB_NAME = "food_list_db";
private final String CREATE_DATABASE = "CREATE TABLE " + FoodContract.FoodList.TABLE_NAME + " ("
        + FoodContract.FoodList._ID + " INTEGER PRIMARY KEY AUTOINCREMENT, "
        + FoodContract.FoodList.ITEM_NAME + " TEXT"
        + ");";

public FoodDatabase(Context context){
    this.context = context;
    databaseHelper = new DatabaseHelper(context);
}

public FoodDatabase openWriteableDB(){
    db = databaseHelper.getWritableDatabase();
    return this;
}

public FoodDatabase openReadableDB(){
    db = databaseHelper.getReadableDatabase();
    return this;
}

public long insertRow(ContentValues cv){
    return db.insert(FoodContract.FoodList.TABLE_NAME,null,cv);
}

public Cursor getAllRows(String[] projection, String selection, String[] selectionArgs, String sortOrder){
    return db.query(FoodContract.FoodList.TABLE_NAME,projection,selection,selectionArgs,null,null,sortOrder);
}

public long deleteRow(long id, String whereClause, String[]whereArgs){
    return db.delete(FoodContract.FoodList.TABLE_NAME,whereClause,whereArgs);
}

public void closeDB(){
    db.close();
}

private class DatabaseHelper extends SQLiteOpenHelper {
    public DatabaseHelper(Context context) {
        super(context, DB_NAME, null, DB_VERSION);
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        db.execSQL(CREATE_DATABASE);

    }

    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        db.execSQL("DROP TABLE IF EXISTS " + FoodContract.FoodList.TABLE_NAME);
        Log.v ("DATABASE", "*********DATABASE DROPPED AND RECREATED*********");
        onCreate(db);
    }
}}

以下是我的主片段中查询语句的样子。从ContentProvider类中检索游标......

        try{
        final Cursor query = getActivity().getContentResolver().query(FoodContract.FoodList.CONTENT_URI, null, null, null, null);
    }catch (Exception e){
        e.printStackTrace();
        Log.v(TAG, "****************Failed to Open**************");
    }

以下是导致应用在我的内容提供商的查询方法中崩溃的声明。再次，我能够检索字符串，但不能检索长ID。有谁知道为什么？

     while(cursor.moveToNext()) {
                    Long id = cursor.getLong(cursor.getColumnIndex(FoodContract.FoodList._ID));
                    String item = cursor.getString(cursor.getColumnIndex(FoodContract.FoodList.ITEM_NAME));
                    Log.v(TAG, "*********id = " + id + " ITEM = " + item + "************");
                }

这是例外

Caused by: java.lang.IllegalStateException: Couldn't read row 0, col -1 from CursorWindow.

Answer 1

您是否曾尝试在.delete_button之前致电cursor.moveToFirst()？

Answer 2

问题出在本声明中：

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
<div id="container"></div>

第二个参数不应为null，而是列或＆＃34;投影＆＃34;返回的光标应该是＆＃34;看着。＆＃34;在这种情况下：

final Cursor query = getActivity().getContentResolver().query(FoodContract.FoodList.CONTENT_URI, null, null, null, null);

在ContentProvider中使用此String []来访问数据库。

使用Cursor检索PRIMARY KEY INTEGER

2 个答案: