JPA单向一对多关系仍然存在

时间:2017-02-07 18:40:54

标签: java jpa one-to-many cascade

我试图通过一对多的关系坚持3个实体,但我无法做到正确。 这就是我所拥有的:

@Entity
@Table(name = "tb_person")
public class Person {
    @Id
    @SequenceGenerator(name = "my_seq", sequenceName = "pk_seq", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "my_seq")
    @Column(name="person_id")
    private long personId;

    @OneToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE})
    @JoinColumn(name = "person_id", referencedColumnName = "person_id")
    private List<Phone> phones;
}


@Entity
@IdClass(PersonBrandId.class)
@Table(name = "tb_person_phone")
public class Phone {
     @Id
     @Column(name = "retailer_id")
     private long personId;

     @Id
     @Column(name = "brand_code")
     private String brandCode;

     @OneToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE})
     @JoinColumns({
        @JoinColumn(name = "brand_code", referencedColumnName = "brand_code", insertable = false, updatable = false),
        @JoinColumn(name = "person_id", referencedColumnName = "person_id", insertable = false, updatable = false)})
     List<Mobile> mobiles;

     ...other fields...
}

@Entity
@Table(name = "tb_mobile")
public class Mobile {
    @Id
    @SequenceGenerator(name = "my_seq2", sequenceName = "pk_seq2", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "my_seq2")
    @Column(name="mobile_id")
    private long mobileId;

    @Column(name = "person_id")
    private long personId;

    ...other fields...
}

所以,我想要达到的目的只是坚持使用Person,因为级联,Phone和Mobile将自动保留。 例如:

Person person = new Person();
Phone phone = new Phone();
Mobile mobile = new Mobile();
phone.getMobiles().add(mobile);
person.getPhones().add(phone);

em.persist(person);

问题是我收到错误,说tb_person_phone.person_id不能为空。

关系是单向的,所以我没有添加ManyToOne端。

为了回答一些评论:

  1. 我只使用JPA
  2. 关系如下:

    人可以有多个电话。

    手机具有复合主键:

       - person_id in Person
    
       - brand_code in Brand (a table with a list of brands)
    

    移动设备具有主键:mobile_id

      has two FK:
    
       - person_id and brand_code both referencing the table Phone 
    
  3. 用于生成表的SQL:

    CREATE TABLE "TB_PERSON"
    (   "PERSON_ID" NUMBER NOT NULL ENABLE, 
    "PERSON_NAME" VARCHAR2(100 BYTE) NOT NULL ENABLE, 
     CONSTRAINT "PERSON_PK" PRIMARY KEY ("PERSON_ID")
    );
    
    
    CREATE TABLE "TB_PERSON_PHONE" 
    (   "PERSON_ID" NUMBER NOT NULL ENABLE, 
        "BRAND_CODE" VARCHAR2(30 BYTE) NOT NULL ENABLE, 
        "ATTR1" VARCHAR2(1 BYTE), 
        "ATTR2" VARCHAR2(100 BYTE), 
     CONSTRAINT "PERSON_PHONE_PK" PRIMARY KEY ("PERSON_ID", "BRAND_CODE")
     FOREIGN KEY ("PERSON_ID")
      REFERENCES "TB_PERSON" ("PERSON_ID") ENABLE, 
     FOREIGN KEY ("BRAND_CODE")
      REFERENCES "TB_BRAND" ("BRAND_CODE") ENABLE
    );
    
    
    CREATE TABLE "TB_MOBILE" 
    (   "MOBILE_ID" NUMBER NOT NULL ENABLE, 
    "PERSON_ID" NUMBER NOT NULL ENABLE, 
    "BRAND_CODE" VARCHAR2(30 BYTE) NOT NULL ENABLE, 
    "NUMBER" VARCHAR2(30 BYTE) NOT NULL ENABLE, 
    "ATTR1" VARCHAR2(100 BYTE), 
    "ATTR2" VARCHAR2(100 BYTE), 
     CONSTRAINT "MOBILE_PK" PRIMARY KEY ("MOBILE_ID"),
     CONSTRAINT "MOBILE_UQ" UNIQUE ("NUMBER", "PERSON_ID", "BRAND_CODE")
     USING INDEX (CREATE UNIQUE INDEX "MOBILE_UQ_IDX" ON "TB_MOBILE" ("NUMBER",       "PERSON_ID", "BRAND_CODE"),
     FOREIGN KEY ("PERSON_ID", "BRAND_CODE")
      REFERENCES "TB_PERSON_PHONE" ("PERSON_ID", "BRAND_CODE") ENABLE
     );
    

2 个答案:

答案 0 :(得分:0)

为移动和电话实体的主键设置@GeneratedValue(strategy = GenerationType.AUTO)

答案 1 :(得分:0)

您正在使用人员ID作为电话类

中的标识符
@Id
 @Column(name = "retailer_id")
 private long personId;

将另一列设为Id并添加一些生成ID策略或

 Person person = new Person();

 em.persist(person); //<

 Phone phone = new Phone();
 Mobile mobile = new Mobile();
 phone.getMobiles().add(mobile);
 person.getPhones().add(phone);

 phone.setPersonId(person.getId()); // <

 em.persist(person);