我有一个带有这个变量的foreach迭代:
$cart = Cart {#167 ▼
+lines: array:2 [▼
0 => CartLine {#168 ▼
+cart_line_id: 989642
+cart_id: 13049301
+parent_line_id: null
+quantity: 1
+article_id: 1164
+article_name: "CUSTOMIZED T-SHIRT"
+pvp: 29.5
}
1 => CartLine {#170 ▼
+cart_line_id: 989643
+cart_id: 13049301
+parent_line_id: 989642
+quantity: 2
+article_id: 199
+article_name: "EXTRA COMPLEMENT"
+pvp: 2.5
}
]
}
这是我的laravel foreach循环:
@foreach ($cart->lines as $line)
@endforeach
我想要这个:
@foreach ($cart->lines as $line)
@if($line->parent_line_id == $line->cart_line_id(previous))
//print extra
@endif
@endforeach
我想获取当前项目迭代的前一项。
这可能吗?
答案 0 :(得分:2)
像这样:
@foreach ($cart->lines as $index => $line)
@if($index > 0 && $line->parent_line_id == $cart->lines[$index - 1]->cart_line_id)
//print extra
@endif
@endforeach
或使用$loop变量(看到您使用5.3):
@foreach ($cart->lines as $line)
@if(!$loop->first && $line->parent_line_id == $cart->lines[$loop->index - 1]->cart_line_id)
//print extra
@endif
@endforeach