Question

我有一个表EmployeeShifts，我在那里插入员工班次。在插入/更新记录之前，我想知道用户是否有任何移位（对于给定的datime范围）。

我尝试了下面的代码，但它不起作用。

declare @Datefrom date
declare @Dateto date
declare @Timefrom nvarchar(200)
declare @Timeto nvarchar(200)

    set @Datefrom ='2017-01-12'
    set @Dateto ='2017-01-30'
    set @Timefrom='03:00 pm'
    set @Timeto='11:30 pm'    

 if exists(select CAST(timefrom as time), CAST(timeto as time),* from EmployeeShifts where [Uid]=11 and Active=1 and        

        ((Datefrom between @Datefrom and @Dateto and 
        ((CAST(timefrom As Time) between CAST(@Timefrom As Time) and  CAST(@Timeto As Time)) or (CAST(timeto As Time) between CAST(@Timefrom As Time) and  CAST(@Timeto As Time))))
        or
         (Dateto between @Datefrom and @Dateto and 
        ((CAST(timefrom As Time) between CAST(@Timefrom As Time) and  CAST(@Timeto As Time)) or (CAST(timeto As Time) between CAST(@Timefrom As Time) and  CAST(@Timeto As Time)))
         )))
          begin
                  print 'User is already in a shift.'                    
         end

我是否需要连接日期和时间来获取日期时间字段？

Answer 1

您的表存在设计问题，导致您执行的工作超出了您的需要。如果在单独的列中有日期和时间值，则总是需要执行额外的工作来执行这样的查询。您应将班次开始时间和结束时间存储为datetime值。看看这个样本，看看你能让你的生活变得多么简单：

CREATE TABLE #EmployeeShifts
    (
      EmployeeId INT ,
      StartTime DATETIME ,
      EndTime DATETIME
    );

INSERT  INTO #EmployeeShifts
        ( EmployeeId, StartTime, EndTime )
VALUES  ( 1, '20170105 09:00:00', '20170105 17:00:00' ),
        ( 1, '20170106 09:00:00', '20170106 17:00:00' ),
        ( 1, '20170107 09:00:00', '20170107 17:00:00' ),
        ( 2, '20170105 09:00:00', '20170105 17:00:00' ),
        ( 2, '20170108 09:00:00', '20170108 17:00:00' ),
        ( 2, '20170109 09:00:00', '20170109 17:00:00' );

DECLARE @from DATETIME = '20170106 07:00:00' ,
        @to DATETIME = '20170108 18:00:00';

SELECT  *
FROM    #EmployeeShifts
WHERE   StartTime BETWEEN @from AND @to
        AND EndTime BETWEEN @from AND @to;

DROP TABLE #EmployeeShifts;

sql时间介于两次之间

1 个答案: