Question

我试图从数据库中获取多个列数据，例如

[{"id":"3","category":"Name","text":"text with some data","image":"http:\/\/examole.net\/folder\/images\/category1.jpg"},{"id":"4","category":"Name","text":"text with some data","image":"http:\/\/examole.net\/folder\/images\/category1.jpg"}]

使用每个语句我无法将其作为json响应

$response = array();
if(isset($_REQUEST['action']) && $_REQUEST['action']=='test'){
        $query="select * from exampledb where id='".$db->escape($_REQUEST['id'])."'";
        $num= $db->num_rows($query);          
        if($num)
        {
            $rows = $db->get_results($query);

            foreach($rows as $row1) { 

                $response['id'] = $row1['id'];
                $response['category'] = $row1['category'];
                $response['text'] = $row1['text'];
                $response['image'] = $row1['image'];
            }       
        }
        else{
            $response['message']='No user Found';
            $response['status']='fail';
        }

    }

Answer 1

在include MyHelper

之后

else

PHP json_encode

<强>更新

else{
            $response['message']='No user Found';
            $response['status']='fail';
        }

echo json_encode($response) //<---- here convert array to json text

PHP从数组中的mysql获取多个数据

1 个答案: