如何在mysql中使用calculate连接查询?
fab_out表
我在下面的查询
SELECT fabric_in.fabric_id, fabric_in.fabric_date, fabric_in.fabric_order_qty, fabric_in.fabric_rejected_qty, fabric_in.fabric_rejected_reason, fabric_in.fabric_total_qty, fabric_in.fabric_company_name, fabric_out.fabric_out_qty
FROM fabric_out
RIGHT JOIN fabric_in
ON fabric_out.fabric_id=fabric_in.fabric_id
答案 0 :(得分:2)
SELECT
fabric_in.fabric_id,
fabric_in.fabric_date,
fabric_in.fabric_order_qty,
fabric_in.fabric_rejected_qty,
fabric_in.fabric_rejected_reason,
fabric_in.fabric_total_qty,
fabric_in.fabric_company_name,
SUM(fabric_out.fabric_out_qty) AS fabric_out_qty
FROM fabric_out
RIGHT JOIN fabric_in
ON fabric_out.fabric_id=fabric_in.fabric_id
GROUP BY fabric_in.fabric_id
答案 1 :(得分:1)
您必须使用MySQL的聚合函数:
SELECT MAX(fabric_in.fabric_id) as fabric_id,
MAX(fabric_in.fabric_date) as fabric_date,
MAX(fabric_in.fabric_order_qty) as fabric_order_qty,
MAX(fabric_in.fabric_rejected_qty) as fabric_rejected_qty,
MAX(fabric_in.fabric_rejected_reason) as fabric_rejected_reason,
MAX(fabric_in.fabric_total_qty) as fabric_total_qty,
MAX(fabric_in.fabric_company_name) as fabric_company_name,
SUM(fabric_out.fabric_out_qty) AS fabric_out_qty
FROM fabric_out
RIGHT JOIN fabric_in
ON fabric_out.fabric_id=fabric_in.fabric_id
GROUP BY fabric_in.fabric_id
这对你有用,没有经过测试。
答案 2 :(得分:0)
作为新版本,您需要将所有列添加为group by或aggravate函数。所以你可以这样使用你的查询。
/path/to/your/project/.git
答案 3 :(得分:0)
试试这个...
SELECT
fabric_in.fabric_id,
fabric_in.fabric_date,
fabric_in.fabric_order_qty,
fabric_in.fabric_rejected_qty,
fabric_in.fabric_total_qty,
fabric_in.fabric_company_name,
a.fabric_out_qty
FROM fabric_in RIGHT JOIN
(select sum(fabric_out_qty) as out_total FROM fabric_out group by fabric_id ) as a ON a.fabric_id=fabric_in.fabric_id;