Question

首先，我将为您提供代码，并简要说明我想要实现的目标。

Code.gs

function onOpen() {
  SpreadsheetApp.getUi() // Or DocumentApp or FormApp.
      .createMenu("Custom Menu")
      .addItem("Show sidebar", "showSidebar")
      .addToUi();
}

function doGet() {
  return HtmlService.createHtmlOutputFromFile("entry");
}

function showSidebar() {
  var html = HtmlService.createHtmlOutputFromFile("entry")
      .setTitle("My custom sidebar")
      .setWidth(300);
  SpreadsheetApp.getUi() // Or DocumentApp or FormApp.
      .showSidebar(html);
}

function EnterData(fobject) {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheetByName("Sheet1");
  sheet.activate();

    ss.toast("Something Happened");

  var range = sheet.getRange(1, 1);
  range.setValue("It worked");
}

function ProgramSuccess() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  ss.toast("Program Run Complete");
}

entry.html

<!DOCTYPE html>
<html>
  <head>
    <base target="_top">
    <script>
      // Prevent form from submitting
      function preventFormSubmit() {
        var forms = document.querySelectorAll('form');
        for (var i = 0; i < forms.length; i++) {
          forms[i].addEventListener('submit', function(event) {
            event.preventDefault();
          });
        }
      }
      window.addEventListener('load', preventFormSubmit);

      function FormSubmit(formObject) {
        google.script.run.withSucessHandler(FormSuccess).EnterData(formObject);
      }
      function FormSuccess() {
        google.script.run.ProgramSuccess;
        google.script.host.close();
      }
    </script>
  </head>

  <body>
    <form id="entryForm" onsubmit="FormSubmit(this)">
      Name:<br>
      <input type="text" name="name">
      <br>
      Client Name:<br>
      <input type="text" name="clientname">
      <br><br>
      <input type="submit" value="Submit">
      <input type="reset">
    </form>
  </body>
</html>

此程序的目的是在Google工作表中打开一个侧边栏，显示一个带有表单（标记）的html页面。然后，当您在html侧栏中单击提交时，它应该在Code.gs中运行EnterData函数。我的问题是这个函数没有运行，当我点击提交按钮时没有任何反应。

对此的任何帮助将不胜感激。

Answer 1

试试这个：

<强> entry.html

<!DOCTYPE html>
<html>
  <head>
    <base target="_top">
    <script>
      // Prevent form from submitting
      function preventFormSubmit() {
        var forms = document.querySelectorAll('form');
        for (var i = 0; i < forms.length; i++) {
          forms[i].addEventListener('submit', function(event) {
            event.preventDefault();
          });
        }
      }
      window.addEventListener('load', preventFormSubmit);

      function FormSubmit() {
        google.script.run.withSucessHandler(FormSuccess).EnterData(document.getElementById("entryForm"));
      }
      function FormSuccess() {
        google.script.run.ProgramSuccess;
        google.script.host.close();
      }
    </script>
  </head>

  <body>
    <form id="entryForm">
      Name:<br>
      <input type="text" name="name">
      <br>
      Client Name:<br>
      <input type="text" name="clientname">
      <br><br>
      <input type="submit" value="Submit" onclick="FormSubmit()">
      <input type="reset">
    </form>
  </body>
</html>

此外，我不明白你为什么要将“entryForm”对象传递给 EnterData 函数，因为你似乎没有使用它。< / p>

Google Apps脚本HTML表单无法提交

1 个答案: