我正在尝试使用bash
重命名目录中与特定模式匹配的所有.txt
个文件。我下面的两次尝试已从目录中删除了文件并引发了错误。谢谢:))
输入
16-0000_File-A_variant_strandbias_readcount.vcf.hg19_multianno_dbremoved_removed_final_index_inheritence_import.txt
16-0002_File-B_variant_strandbias_readcount.vcf.hg19_multianno_dbremoved_removed_final_index_inheritence_import.txt
所需的输出
16-0000_File-A_multianno.txt
16-0002_File-B_multianno.txt
Bash尝试1 this removes the files from the directory
for f in /home/cmccabe/Desktop/test/vcf/overall/annovar/*_classify.txt ; do
# Grab file prefix.
p=${f%%_*_}
bname=`basename $f`
pref=${bname%%.txt}
mv "$f" ${p}_multianno.txt
done
Bash尝试2 Substitution replacement not terminated at (eval 1) line 1.
for f in /home/cmccabe/Desktop/test/vcf/overall/annovar/*_classify.txt ; do
# Grab file prefix.
p=${f%%_*_}
bname=`basename $f`
pref=${bname%%.txt}
rename -n 's/^$f/' *${p}_multianno.txt
done
答案 0 :(得分:3)
您不需要循环。仅rename
可以做到这一点:
rename -n 's/(.*?_[^_]+).*/${1}_multianno.txt/g' /home/cmccabe/Desktop/test/vcf/overall/annovar/*_classify.txt
正则表达式的含义大致是,
捕获从开始到第二个_
的所有内容,
匹配其余的,
并用捕获的前缀替换并附加_multianno.txt
使用-n
标志,此命令将打印它将执行的操作而不实际执行此操作。
当输出看起来不错时,请删除-n
并重新运行。