Question

我尝试在所有ajax调用完成后调用一次函数。下面的$.when过早被调用，其中包含一系列空白。从之前几次searchRecommendations()次呼叫成功以来，$.ajax被多次呼叫。这可能会以某种方式负责吗？

var MAX = 2; //Maximum levels queried
var ARTISTS = [];  //Multidimensional array with the number of potential 'artists' i.e. compare Madonna, to Beethoven to Eminem to nth-artist
var RELEVENT_ARTISTS = 2; //Number of relevent artists added to the list for each new artist 
var promises = []; 

 $(function(){
    init(0);
 })


   function init(i){
   for(var i; i<1; i++){

        console.log('searchArtists for relevant artist '+$('input')[i].value)   
        var artist = $('input')[i].value;
        $.ajax({
            url: 'https://api.spotify.com/v1/search',
            data: {
                q: artist,
                type: 'artist'
            },
                success: function (response) {
                    console.log(response.artists.href);
                    searchRecommendations(response.artists.items[0].id, 0)  
                    //nextLevel(0)
            }
        });


    }
    //console.log(ARTISTS)  
    //getMatches(ARTISTS)   
}



function searchRecommendations(artist, depth) {
            console.log(' ')                
            console.log('searchRecommendations '+artist+ ' '+ depth )   
            if(depth == MAX){ return console.log('max reached '+depth) } else {
                    promises.push(
                        $.ajax({
                            url: 'https://api.spotify.com/v1/artists/' + artist + '/related-artists',
                            data: {
                                type: 'artist',
                            },
                            success: function (response) {

                                console.log('RESPONSE');
                                console.log(response)
                                for(var r=0; r<RELEVENT_ARTISTS; r++){
                                    console.log(response.artists[r].name)
                                    var obj = { 'artist' : response.artists[r].name,  'level':(depth+1)*5 } 

                                    ARTISTS.push(obj)

                                    searchRecommendations(response.artists[r].id, depth+1)  //Recursion
                                }
                            }       
                        })
                    )
            }   
}





$.when.apply(undefined, promises).done(function() {
    convert_artists_to_nodes_and_links(ARTISTS)
    console.log( 'this is being called too soon')
    console.log( promises )
})

How to wait until jQuery ajax request finishes in a loop?

Answer 1

好的，对你的代码进行大量重构，但我认为这会做你想做的事 - 抱歉我无法测试它 - 我会尝试慢慢添加注释来解释代码

function init(i) {
    // $('input.artist') - as I can't see your HTML, I would recommend adding cclass='artist' to inputs that you want to process
    // [].map.call($('input.artist'), function(artist, i) { - iterate through the inputs, calling the function which returns a promise
    // artistP will be an array of Promises
    var artistsP = [].map.call($('input.artist'), function(artist, i) {
        console.log('searchArtists for relevant artist ' + $('input')[i].value)
        var artist = $('input')[i].value;
        // return the promise returned by $.ajax
        return $.ajax({
            url: 'https://api.spotify.com/v1/search',
            data: {
                q: artist,
                type: 'artist'
            }
        })
        // the returned promise needs to wait for the promise returned by searchRecommendations
        .then(function(response) {
            console.log(response.artists.href);
            return searchRecommendations(response.artists.items[0].id, 0);
        });
    });
    // wait for the promises to complete and we're done
    $.when.apply($, artistsP).done(function() {
        convert_artists_to_nodes_and_links(ARTISTS)
    });
}

function searchRecommendations(artist, depth) {
    console.log('searchRecommendations ' + artist + ' ' + depth)
    if (depth == MAX) {
        // just return undefined to stop the recursion
        return console.log('max reached ' + depth);
    } else {
        // return a promise
        return $.ajax({
            url: 'https://api.spotify.com/v1/artists/' + artist + '/related-artists',
            data: {
                type: 'artist',
            }
        })
        // the promise needs to wait for the recursed artists
        .then(function(response) {
            // create an array of promises to wait on
            var promises = response.artists.map(function(artist) {
                console.log(artist.name)
                var obj = {
                    'artist': artist.name,
                    'level': (depth + 1) * 5
                }
                ARTISTS.push(obj)
                return searchRecommendations(response.artists[r].id, depth + 1) //Recursion
            });
            // return a promise that waits for all the "sub" requests
            return $.when.apply($, promises);
        });
    }
}

等待所有ajax调用完成后才能使用$ .when

1 个答案: