Question

我在upstart中添加了ponzu-server，但是我启动ponzu-server有一些错误。

sudo service ponzu-server start
Job for ponzu-server.service failed because the control process exited with error code. See "systemctl status ponzu-server.service" and "journalctl -xe" for details.

journalctl -xe：

Jan 28 19:12:22 cs67724 systemd[1]: ponzu-server.service: Unit entered failed state.
Jan 28 19:12:22 cs67724 systemd[1]: ponzu-server.service: Failed with result 'exit-code'.
Jan 28 19:12:22 cs67724 sudo[1069]: pam_unix(sudo:session): session closed for user root
Jan 28 19:12:30 cs67724 sudo[1095]:    ponzu : TTY=pts/0 ; PWD=/home/ponzu/work ; USER=root ; COMMAND=/bin/journalctl -xe
Jan 28 19:12:30 cs67724 sudo[1095]: pam_unix(sudo:session): session opened for user root by ponzu(uid=0)
Jan 28 19:13:14 cs67724 sudo[1095]: pam_unix(sudo:session): session closed for user root
Jan 28 19:16:58 cs67724 sudo[1118]:    ponzu : TTY=pts/0 ; PWD=/home/ponzu/work/src/remoteConfig/deployment/sysv ; USER=root ; COMM
Jan 28 19:16:58 cs67724 sudo[1118]: pam_unix(sudo:session): session opened for user root by ponzu(uid=0)

Answer 1

这通常是因为没有在作为Ponzu项目中的示例提供的init脚本中分配$ VARIABLES。

在尝试启动守护程序/服务之前，请确保添加自己的项目目录路径和其他变量。

服务upstrart进程退出并显示错误代码

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