我有一个问题,我需要一个解决的想法:)
我有2次调用$ .ajax 首先,是asynch,并且在很长一段时间内(例如1分钟) 第二,是同步(在ajax async:false中)并且它快速响应(例如5秒)
第二次呼叫处于循环中(请求 - >响应 - >打印数据,请求 - >响应 - >打印数据)。 我需要在第一次完成(成功或错误)时,停止第二次通话。
我附上了一个示例代码:
var success = false;
$.ajax({
type: "POST",
url: urlRest,
data: {
data: dataSend
},
success: processOK,
error: processError
});
do {
$.ajax({
type: "POST",
url: urlData,
data: {
data: dataSend
},
async: false,
success: function(data, textStatus, jqXHR){
console.log(data);
},
error: function(data, textStatus, jqXHR){
console.log("Error");
}
});
} while (!success);
我希望它清楚:))
答案 0 :(得分:0)
我纠正了会导致一些错误的问题,请尝试一下。
let printData = function( input ){
let config = {
urlRest: '',
data: { data: {} },
loop: false,
callback: false
}
$.each(config,function(k,v){ config[k] = input[k] });
config.loop = false;
$.ajax({
type: 'POST',
url: config.urlRest,
data: config.data,
success: function( data ){
// Based on the response if you need to run again change config.loop to true and it will run again
// you can also alter anything your sending through
if( config.loop ) printData( config );
else if( typeof config.callback === 'function' ) callback();
},
error: function(){
// Based on the response if you need to run again change config.loop to true and it will run again
// you can also alter anything your sending through
if( config.loop ) printData( config );
else if( typeof config.callback === 'function' ) callback();
}
});
}
printData({
urlRest: '', // URL Here
data: data, // Data Object
loop: true, // Set this to true if you want it to loop
callback: function(){
console.log( 'Job Complete' );
}
})
答案 1 :(得分:0)
您可以使用SynJS以同步方式运行异步调用:
function ajaxWrapper(ctx, url, data){
var res={done:false};
$.ajax({
type: "POST",
url: url,
data: data,
success: function(result){
res.data=result;
},
error: function(){
res.error=true;
},
}).always(function(){
res.done = true;
SynJS.resume(ctx); // <-- tell caller that callback is finished
});
return res; // <-- return object that will hold the results
}
// function that is executed in synchronous manner
function myFunc(modules, urlRest, urlData) {
var success = false;
var res1 = modules.ajaxWrapper(_synjsContext, urlRest, urlData);
SynJS.wait(res1.done); // <-- wait for result from callback
do {
var res2 = modules.ajaxWrapper(_synjsContext, urlRest, urlData);
SynJS.wait(res2.done); // <-- wait for result from 2nd callback
} while (!success);
}
var modules = {ajaxWrapper: ajaxWrapper};
SynJS.run(myFunc,null, modules, "/", {}, function () {
console.log('done');
});
答案 2 :(得分:-1)
您可以像这样更改成功值
order
或者你可以创建一个自我调用函数(在第二次ajax完成之后,再次调用它)但在调用之前它会像@mplungjan那样检查成功变量。
答案 3 :(得分:-1)
循环Ajax永远不是一个好主意。您需要允许呼叫返回。 这是一个不使用async false的示例
var firstDone = false,tId;
// call long ajax
$.ajax({
type: "POST",
url: urlRest,
data: {
data: dataSend
}
}).done(processOK);
}).fail(processError)
}).always(function() {firstDone=true; clearTimeout(tId);}); // stops the other loop
// setup function that can be looped
function callAjax() {
if (firstDone) return;
$.ajax({
type: "POST",
url: urlData,
data: {
data: dataSend
}
}).done(function(data, textStatus, jqXHR) {
console.log(data);
}).fail(function(data, textStatus, jqXHR) {
console.log("Error");
}).always(function() {
tId=setTimeout(callAjax,1000); // give the server time to recover
});
}
callAjax();
&#13;